[R] How to open a file with a name changed?

[Steve Taylor]

You probably want to use paste or paste0 instead of cat.
paste0(cit,dia,extension)

Also, this might work: 
tail(dir("C:/Bonos/",patt="csv$"),1)


-----Original Message-----
From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org] On Behalf Of Minerva Mora
Sent: Friday, 25 May 2012 11:45a
To: r-help at r-project.org
Subject: [R] How to open a file with a name changed?

Hi, I apologize for my english.

I´m trying to read a file, but the name of this file changes every day, for
example: today is May 24, 2012

bonos<- read.table("C:/Bonos/*20120524*.csv", header=TRUE, sep="\t")

So, tomorrow I want to read the file again, but i don´t want to put the date
by myself, i want this automatically. I know that if a put day() this
instruccion gives me the date.

My problem is, I don´t know how to concatenate these:
-"C:/Bonos/
-the date
-.csv"
 
I tried this:
bonos<- read.table(cat(cit,dia,extension), header=TRUE, sep="\t")
where
--cit is *"\"C:/Bonos/"*
--dia is *dia<-format(today, "%Y%m%d")*
--extension is *extension<-".csv\""*

but i have this problem:
"C:/Bonos/ 20120524 .csv"*Error in read.table(cat(cit, dia, extension),
header = TRUE, sep = "\t") : * * 'file' must be a character string or
connection*

What can i do?

Thanks!

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