[R] Deleting row labels in dataframe

[arun]

HI David,

My intention was to get the output in the format:

 Price Floor Area Rooms Age Cent.heat
    52   111  830     5 5.2        no
    54   128  710     5 6.2        no
    57   101 1000     5 3.8        no
    57   138  690     5 4.5        no
    59    93  780     5 6.8       yes


which was accomplished from Peter's code:

> print(HousePriceT1,row.names=FALSE).
In the output given below by you, it is still having the rownumbers (1,2,3,4,5) which I wanted to eliminate.

Thanks for the reply.

A.K.



----- Original Message -----
From: David Winsemius <dwinsemius at comcast.net>
To: Peter Ehlers <ehlers at ucalgary.ca>
Cc: arun <smartpink111 at yahoo.com>; R help <r-help at r-project.org>
Sent: Tuesday, May 22, 2012 9:48 PM
Subject: Re: [R] Deleting row labels in dataframe


On May 22, 2012, at 6:30 PM, Peter Ehlers wrote:

> On 2012-05-22 13:55, arun wrote:
>> Dear R group,
>> 
>> I was working on an example dataset to see if the row labels can be deleted.   I know that header=TRUE could be used when we use read.table.  In the data.frame, I tried to delete row labels 1,2,..5, but so far not successful.  Is there a neat way to do it.
>> 
> 
> What are you trying to accomplish? Save the dataframe without
> rownames?
> Use write.table(..., row.names=FALSE)
> 
> Print it in the console without rownames?
> Use print(..., row.names=FALSE)
> 
Notice that Peter Ehlers, an accomplished useR, has _not_ told you how to remove row.names from dataframes.

> attr(HousePriceT1, "rownames") <- NULL
> HousePriceT1
  Price Floor Area Rooms Age Cent.heat
1    52   111  830     5 5.2        no
2    54   128  710     5 6.2        no
3    57   101 1000     5 3.8        no
4    57   138  690     5 4.5        no
5    59    93  780     5 6.8       yes


--David.

> Peter Ehlers
> 
>> Thanks.
>> A.K.
>> 
>> 
>> HousePriceT1<-structure(list(Price = c(52, 54, 57, 57, 59), Floor = c(111,
>> 128, 101, 138, 93), Area = c(830, 710, 1000, 690, 780), Rooms = c(5,
>> 5, 5, 5, 5), Age = c(5.2, 6.2, 3.8, 4.5, 6.8), Cent.heat = structure(c(1L,
>> 1L, 1L, 1L, 2L), .Label = c("no", "yes"), class = "factor")), .Names = c("Price",
>> "Floor", "Area", "Rooms", "Age", "Cent.heat"), row.names = c(NA,
>> -5L), class = "data.frame")
>> 
> 
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David Winsemius, MD
West Hartford, CT