[R] Subtracting a matrix 1x28 from a scalar

[David Winsemius]

On May 7, 2012, at 3:26 PM, meredith wrote:

> Afternoon-
>  I am trying to subtract a matrix, basically a vector of 28 values,  
> each by
> the same number to account for differences in regression fitting. I am
> taking the 1x28 and minus it by the mean value of the matrix, each  
> number.
> The result I receive is a 1X29 matrix.

No. You simply do not understand what you are looking at that is NOT a  
matrix, but rather a 34 element vector. The [28] and hte [29] refer to  
the item location of the succeeding value.

-- 
David.
> Does anyone know why the result has
> an extra value?
>
>> lffeb_march
> [1] 6.588926 7.663877 6.917706 6.824374 7.029973 6.549651 6.517671  
> 6.070738
> 5.916202
> [10] 6.993933 6.091310 7.313220 5.135798 6.762730 6.381816 7.999679  
> 6.851185
> 5.799093
> [19] 7.774856 6.956545 8.218787 8.218787 7.549609 7.222566 7.170120  
> 6.173786
> 5.075174
> [28] 4.700480 6.672033 5.198497 4.867534 7.170120 6.131226 6.802395
>> meanf_fm<-mean(lffeb_march)
>> X3_fm<-(lffeb_march-meanf_fm)
>> X3_fm
> [1] -0.03784990  1.03710088  0.29092923  0.19759729  0.40319653  
> -0.07712564
> -0.10910511
> [8] -0.55603865 -0.71057432  0.36715660 -0.53546650  0.68644401  
> -1.49097794
> 0.13595313
> [15] -0.24496036  1.37290220  0.22440855 -0.82768372  1.14807939   
> 0.32976906
> 1.59201078
> [22]  1.59201078  0.92283279  0.59578964  0.54334317 -0.45299027  
> -1.55160256
> -1.92629601
> [29]  0.04525657 -1.42827935 -1.75924193  0.54334317 -0.49554989   
> 0.17561839
>
> Thanks for the help
> Meredith
>
> --
> View this message in context: http://r.789695.n4.nabble.com/Subtracting-a-matrix-1x28-from-a-scalar-tp4615590.html
> Sent from the R help mailing list archive at Nabble.com.
>
> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.

David Winsemius, MD
West Hartford, CT