[R] Breaking up a Row in R (transpose)
Petr Savicky
savicky at cs.cas.cz
Fri May 4 22:42:40 CEST 2012
On Fri, May 04, 2012 at 11:11:47AM -0700, marc212 wrote:
> I have something like 28 rows and 6000 columns. How would I configure this
> with for loops.
The transformation may be splitted into simpler pieces using a for
loop over the 28 rows. Try the following.
orig <- rbind(
"0"=c(5, 6, 6, 7, 7, 9),
"1"=c(3, 4, 4, 3, 9, 9),
"2"=c(5, 2, 6, 4, 7, 4))
colnames(orig) <- rep(c("x", "y"), times=3)
out <- matrix(nrow=ncol(orig)/2, ncol=2*nrow(orig))
for (i in seq.int(length=nrow(orig))) {
out[, 2*(i-1) + 1:2] <- matrix(orig[i, ], nrow=nrow(out), ncol=2, byrow=TRUE)
}
out
[,1] [,2] [,3] [,4] [,5] [,6]
[1,] 5 6 3 4 5 2
[2,] 6 7 4 3 6 4
[3,] 7 9 9 9 7 4
Hope this helps.
Petr Savicky.
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