[R] subtract a list of vectors from a list of data.frames in an elegant way

[Eric Fail]

a working solution to the problem,

 a <- DBquery[names(lookup)]

mother.of.lookup <- list()
for(string in names(a)) {
   a[[string]] <- names(a[[string]])
   mother.of.lookup[[string]] <- setdiff(a[[string]], lookup[[string]])
}

identical(mother.of.lookup, result)

It might not be the most elegant solution, but it works.

Best,
Eric

On Thu, Mar 29, 2012 at 4:07 AM, Jim Holtman <jholtman at gmail.com> wrote:
>
> ?setdiff
>
> Sent from my iPad
>
> On Mar 29, 2012, at 4:28, "Eric Fail" <eric.fail at gmx.us> wrote:
>
> > Dear R experts,
> >
> > I've realized that it might not be possible to define a negative SELCET statement in a SQL call so now I'm looking for the smoothest way to generate a list of what I would like from my large database by first pulling all the names with a query like this "SELECT top 1 * FROM your_table" (thank you Bart Joosen for the idea) and then subtract the variables I am not allow to pull manually ending up with a 'positive' definition of what I want, something I can use in a SQL SELCT statement (see my email on this list from yesterday for more on that).
> >
> > When I query the database for the variable names I get something similar to 'DBquery' in my working example below, but considerable longer with over 2400 hundred variables. As I only need to remove two or three variables I would like to define a lookup table (like the list 'lookup' in my example) and subtract that from my data base query. Now to my question. Is there a way I can subtract one list from another? Like setoff or alike?
> >
> > I would like to end up with a list like the one shown in my example called 'result.' In short, I would like to subtract 'lookup' from 'DBquery' and end up with 'result,' please note that 'result' is a list fo vecktors and not a list of dataframes. In my real life example DBquery is considerable longer so defining that by hand would make a really really long syntax.
> >
> > Hope someone know some smart function that I can use to solve my problem in an elegant way.
> >
> > Thanks for reading.
> >
> > Erick
> >
> > ###### begin R code ######
> >
> > DBquery     <- list(tableA=data.frame(id = numeric(0), atwin = numeric(0), atrout = numeric(0)),
> >                    tableB=data.frame(id = numeric(0), mq   = numeric(0), z = numeric(0), m = numeric(0)),
> >                    tableC=data.frame(V1 = numeric(0), mfn   = numeric(0), iiff = numeric(0)),
> >                    tableD=data.frame(id    = numeric(0), msf   = numeric(0), oom  = numeric(0)))
> >
> > lookup     <- list(tableA=   c('atwin', 'atrout'),
> >                   tableB=    c('m', 'z'),
> >                   tableC=    'ALL')
> >
> > ### ...
> >
> > result     <- list(tableA= c('id'),
> >                    tableB= c('id', 'mq'),
> >                    tableC= c('V1', 'mfn', 'iiff'))
> >
> > ______________________________________________
> > R-help at r-project.org mailing list
> > https://stat.ethz.ch/mailman/listinfo/r-help
> > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> > and provide commented, minimal, self-contained, reproducible code.