[R] Using object as literal value in list vector

ROLL Josh F JRoll at lcog.org
Wed Jun 20 22:15:17 CEST 2012


Yes I feel foolish as this was the solution I finally came up with.  It came to me in the shower, once I was able to pull myself out of the code and think for a while.  Thanks for you insights  

JR 

-----Original Message-----
From: arun [mailto:smartpink111 at yahoo.com] 
Sent: Wednesday, June 20, 2012 1:14 PM
To: ROLL Josh F
Cc: R help
Subject: Re: [R] Using object as literal value in list vector

Hi,

You can try:

NewMeans<-split(matrix(unlist(MeanValues_)*0.80),1:nrow(matrix(unlist(MeanValues_)*0.80)))
names(NewMeans)<-names(MeanValues_)

NewMeans
$ACC
[1] 800

$RTL
[1] 1600

$WHL
[1] 2400




A.K.



----- Original Message -----
From: LCOG1 <jroll at lcog.org>
To: r-help at r-project.org
Cc: 
Sent: Tuesday, June 19, 2012 8:31 PM
Subject: [R] Using object as literal value in list vector

Hello all ,
  This is a pretty simple question I think but cannot find an answer on the list or in my brain.  I would like to iterate through a loop and use a vector of strings to name a number of list elements.  For instance 

       #Create vector of strings
    Et<- c("ACC","RTL","WHL")
    MeanValues_ <- list("ACC" = 1000, "RTL" = 2000, "WHL" = 3000)

    #Iterate through each element of vector
    NewMeans_ <- list()
    for(et in Et){
        NewMeans_ <- c(NewMeans_,list(et = unlist(MeanValues_[et]) * .80 ))
    }

Returns
> NewMeans_
$et
ACC
800 

$et
RTL
1600 

$et
WHL
2400 

But I want 'et' to be the object value of et, so it would be $ACC, $RTL, and $WHL.  I realize there may be another way to actually do what I want to do as far as applying the calculation but I have a bunch of code structured around the need for my list coming in a certain way.  Thanks

Josh

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