[R] noob requesting help
Rui Barradas
ruipbarradas at sapo.pt
Mon Jun 18 13:38:58 CEST 2012
Hello,
Have you tried what I wrote in my last post?
Revised:
# Make a copy first, and operate on the copy.
dep <- departures
names(dep) <- NULL
dep <- data.frame(dep)
Rui Barradas
Em 18-06-2012 11:09, capital_P escreveu:
>
> David Winsemius wrote
>>
>> That's going to remove a lot of rows.
>>
>> Since you are not telling us what columns correspond to those
>> concepts, I'm going to use the terms you are. Something along the
>> lines of:
>>
>> require(lattice)
>> histogram( ~ hours | bird, data=dat2, nint =24 , xlim=c(0,24))
>> histogram( ~ hours , data=dat2, nint =24 , xlim=c(0,24))
>>
>> The result on that example was just a list with one element, a
>> dataframe.
>>
>> > str(departures)
>> List of 1
>> $ 121.3:'data.frame': 1 obs. of 4 variables:
>> ..$ device_info_serial: int 121
>> ..$ hour : int 10
>> ..$ time : POSIXct[1:1], format: "2009-05-21 04:59:24"
>> ..$ tripID : int 3
>>
>> So to get what you might have expected
>>
>> > dep <- departures[[1]]
>> > dep
>> device_info_serial hour time tripID
>> 1 121 10 2009-05-21 04:59:24 3
>>
>> But since you didn't actually describe what you did want (or if you
>> did you left upthread), its only a guess.
>>
>
> I'll try to explain my goals more clearly.
>
> The columns are:
>
> dat2$device_info_serial: The 'number' of the bird, ranging from 121 to 542.
> There are 34 different birds, each with their own number.
>
> dat2$tripID: The number of the trip. Every bird has a trip 1, 2, 3, etc.
> (some birds have as much as 265 trips, many have less). Every trip has many
> measurements, as trips take hours and measurements were taken every 15
> minutes.
>
> dat2$time: The time at which a measurement was taken.
>
> dat2$hour: The 'hour' part of dat2$time; the hour in which a measurement was
> taken
>
>
>>From my dataset, I need to gather only the first measurement of every trip
> of every bird. This way, I can make (circular) graphs of the departure-times
> for each trip of each bird. I think that I am very close after using:
>
> departures <- lapply(split(dat2, list(dat2$device_info_serial,
> dat2$tripID)), function(x) x[x$time == min(x$time),])
>
> But it is in the wrong format. I need it to be in a format so that I can use
> commands such as departures$hour and departures$device_info_serial. I need
> this so that I can circulise (circularise?) dat2$hour and so that I can make
> graphs for each bird seperately.
>
> Making the graphs etc. shouldn't be a problem if I have a dataset that I can
> use like this:
>
> d121 <- departures[which(departures$device_info_serial == 121),]
> d130 <- departures[which(departures$device_info_serial == 130),]
> d132 <- departures[which(departures$device_info_serial == 132),]
> d133 <- departures[which(departures$device_info_serial == 133),]
>
> and
>
> cdAll <- circular(departures$hour, units='hours', template='clock24')
> cd121 <- circular(d121$hour, units='hours', template='clock24')
> cd130 <- circular(d130$hour, units='hours', template='clock24')
> cd132 <- circular(d132$hour, units='hours', template='clock24')
>
> So, if I'm not mistaken, I only need your help with transforming the
> 'departures' that I have now into something with $hour and
> $device_info_serial. I hope this is possible.
>
> I hope my ignorance isn't frustrating you too much. I'm trying my best to
> understand and learn how to work with R in the short timespan that I have.
>
> Peter
>
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