[R] R sub query

jim holtman jholtman at gmail.com
Mon Jul 2 15:01:39 CEST 2012

```Will this do:

> m<-matrix(c(".:0:0,0", ".:2:0,2", ".:194:193,1", ".:56:0,56", ".:58:50,8", ".:13:0,13",  ".:114:114,0", ".:75:75,0"), nrow=2)
>
> m
[,1]      [,2]          [,3]        [,4]
[1,] ".:0:0,0" ".:194:193,1" ".:58:50,8" ".:114:114,0"
[2,] ".:2:0,2" ".:56:0,56"   ".:13:0,13" ".:75:75,0"

> sub("^\\.:[^:]*:", "", m)
[,1]  [,2]    [,3]   [,4]
[1,] "0,0" "193,1" "50,8" "114,0"
[2,] "0,2" "0,56"  "0,13" "75,0"
>

On Mon, Jul 2, 2012 at 4:15 AM, Sarah Auburn <sauburn at yahoo.com> wrote:
> Hello,
> I would like to substitute a substring of characters defined by a specific start and end sequence.
> i.e. in the example matrix below, I would like to substitute ".:X:" with "", where X varies in sequence...
>
> m<-matrix(c(".:0:0,0", ".:2:0,2", ".:194:193,1", ".:56:0,56", ".:58:50,8", ".:13:0,13",  ".:114:114,0", ".:75:75,0"), nrow=2)
>
> output required:
>      [,1]      [,2]          [,3]        [,4]
> [1,] "0,0" "193,1" "50,8" "114,0"
> [2,] "0,2" "0,56"   "0,13" "75,0"
>
> Thank you for any help
> Sarah
>         [[alternative HTML version deleted]]
>
>
> ______________________________________________
> R-help at r-project.org mailing list
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> and provide commented, minimal, self-contained, reproducible code.
>

--
Jim Holtman
Data Munger Guru

What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.

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