[R] 2 sample wilcox.test != kruskal.test

[syrvn]

Hi,

thanks for your answer. Unfortunately I cannot reproduce your results.

In my example the results still differ when I use your approach:

> x <- c(10,11,15,8,16,12,20)
> y <- c(10,14,18,25,28,30,35)
> f <- as.factor(c(rep("a",7), rep("b",7)))
> d <- c(x,y)
> kruskal.test(x,y)

	Kruskal-Wallis rank sum test

data:  x and y 
Kruskal-Wallis chi-squared = 6, df = 6, p-value = 0.4232

> kruskal.test(x~y)

	Kruskal-Wallis rank sum test

data:  x by y 
Kruskal-Wallis chi-squared = 6, df = 6, p-value = 0.4232

> kruskal.test(d~f)

	Kruskal-Wallis rank sum test

data:  d by f 
Kruskal-Wallis chi-squared = 3.6816, df = 1, p-value = 0.05502

> kruskal.test(f~d)

	Kruskal-Wallis rank sum test

data:  f by d 
Kruskal-Wallis chi-squared = 11.1429, df = 12, p-value = 0.5167


I know the last kruskal.test(f~d) is not correct as the factor is always
placed as the second bit but I still tried it that way just to be sure...

Cheers


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