[R] Convert components of a list to separate columns in a data frame or matrix XXXX
Rui Barradas
ruipbarradas at sapo.pt
Sun Jan 8 20:31:39 CET 2012
Hello,
I believe this solves your problem
fun <- function(x){
f <- function(x, n){
if(length(x) < n) x <- c(x, rep(NA, n-length(x)))
return(x)
}
lapply(x, f, max(unlist(lapply(x, length))))
}
fun(result) # the 'result' list above
list2 <- list(x=1:3, y=1:5, z="abc")
fun(list2)
The function returns a list, then it can be made a matrix, a data.frame or
whatever.
Rui Barradas
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