[R] Creating ZOO Matrix from Data Frame
Rich Shepard
rshepard at appl-ecosys.com
Mon Jan 2 17:31:38 CET 2012
I believe that I have a basic understanding of zoo and how to use read.zoo
on a text file, What I have not seen in the zoo help files and vignettes is
how to convert a data frame to a zoo matrix for irregular time series
analyses.
An example data frame is structured like this:
str(burns.cast)
'data.frame': 256 obs. of 47 variables:
$ site : Factor w/ 143 levels "BC-0.5","BC-1",..: 1 1 1 2 2 2 2 2 2 2
$ sampdate : Date, format: "1996-04-19" "1996-05-21" ...
$ Ca : num 76.6 NA NA NA NA ...
$ Cond : num 712 403 731 NA NA NA NA NA NA NA ...
$ HCO3 : num 162 152 212 NA NA NA NA NA NA NA ...
$ SO4 : num 175 57 194 NA NA NA NA NA NA NA ...
$ TDS : num 460 212 530 NA NA NA NA NA NA NA ...
...
What I think I need is a matrix that orders sampdate, has the numeric
values for TDS, and retains the factor of site (so that I can compare TDS
values on a given date by site). The August 2011 version of zoo docs
suggests that I need to modify the above from a data frame to a matrix, but
there is more than a single class involved.
Would something like this work?
z <- zoo(burns.cast$TDS, order.by = burns.cast$sampdate, style = vertical)
And where do I include the site factor?
A pointer to docs or an example will be much appreciated.
Rich
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