[R] Sorting strings

[De-Jian Zhao]

It seems OS-dependent. I got different results when trying it on windows 
xp and Redhat linux.


 > R.version
                _
platform       x86_64-unknown-linux-gnu
arch           x86_64
os             linux-gnu
system         x86_64, linux-gnu
status
major          2
minor          9.1
year           2009
month          06
day            26
svn rev        48839
language       R
version.string R version 2.9.1 (2009-06-26)
 > sort(c("X.","X0B"))
[1] "X."  "X0B"
 > sort(c("X.Z","X0B.Z"))
[1] "X.Z"   "X0B.Z"


 > R.version
                _
platform       x86_64-unknown-linux-gnu
arch           x86_64
os             linux-gnu
system         x86_64, linux-gnu
status
major          2
minor          9.1
year           2009
month          06
day            26
svn rev        48839
language       R
version.string R version 2.9.1 (2009-06-26)
 > sort(c("X.","X0B"))
[1] "X."  "X0B"
 > sort(c("X.Z","X0B.Z"))
[1] "X0B.Z" "X.Z"


On 2012-2-20 23:27, statquant2 wrote:
> Ok I have :
>
> R) str(R.Version())
> List of 13
>   $ platform      : chr "x86_64-unknown-linux-gnu"
>   $ arch          : chr "x86_64"
>   $ os            : chr "linux-gnu"
>   $ system        : chr "x86_64, linux-gnu"
>   $ status        : chr ""
>   $ major         : chr "2"
>   $ minor         : chr "12.2"
>   $ year          : chr "2011"
>   $ month         : chr "02"
>   $ day           : chr "25"
>   $ svn rev       : chr "54585"
>   $ language      : chr "R"
>   $ version.string: chr "R version 2.12.2 (2011-02-25)"
>
> R) sort(c("X.","X0B"))
> [1] "X."  "X0B"
> R) sort(c("X.Z","X0B.Z"))
> [1] "X0B.Z" "X.Z"
>
> I am using a linux redHat
> $ uname -a
> Linux 2.6.18-238.9.1.el5 #1 SMP Fri Mar 18 12:42:39 EDT 2011 x86_64 x86_64
> x86_64 GNU/Linux
>
>
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