[R] help in run if

William Dunlap wdunlap at tibco.com
Wed Feb 15 18:37:42 CET 2012


runif's min and max argument may be vectors:
  > x=c(0,0,0,0,0)
  > y=c(10,20,30,40,50)
  > runif(length(y), min=x, max=y)
  [1]  7.005180 14.035296  9.388089 22.094211 43.624606

This is equivalent to x + (y-x)*runif(length(y)) but
such a transformation is not always so easy for nonuniform
random number generators.  All the standard rng's
accept vectors of parameters.
 
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com 

> -----Original Message-----
> From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org] On Behalf Of Petr Savicky
> Sent: Wednesday, February 15, 2012 1:12 AM
> To: r-help at r-project.org
> Subject: Re: [R] help in run if
> 
> On Wed, Feb 15, 2012 at 12:31:54AM -0800, arunkumar1111 wrote:
> > hi
> >
> > My data looks like
> >
> > x=c(0,0,0,0,0)
> > y=c(10,20,30,40,50)
> >
> > i want to generate 5 random numbers  between x and y  keeping x values as
> > min and y value as max using apply
> >
> > it takes time when it is run using for
> 
> Hi.
> 
> A solution without a loop is
> 
>   x + (y - x)*runif(length(x))
> 
> Hope this helps.
> 
> Petr Savicky.
> 
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