[R] fill an array by rows

[William Dunlap]

Use aperm on the output of array:
  > aperm(array(1:8, dim=c(2,2,2)), perm=c(2,1,3))
  , , 1
  
       [,1] [,2]
  [1,]    1    2
  [2,]    3    4

  , , 2

       [,1] [,2]
  [1,]    5    6
  [2,]    7    8

Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com 

> -----Original Message-----
> From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org] On Behalf Of Jim Maas
> Sent: Thursday, February 09, 2012 9:47 AM
> To: r-help at r-project.org
> Subject: [R] fill an array by rows
> 
> I've dug around but not been able to find anything, am probably missing
> something obvious.
> 
> How can I fill a three-dimensional (or higher dimension) array by rows
> instead of columns.
> 
> eg
> 
> new1 <- array(c(1:125), c(5,5,5))
> 
> works fine for me but fills it by columns and
> 
> new2 <- array(c(1:125), c(5,5,5), byrow=TRUE)
> 
> throws an error.
> 
> Am I missing something obvious?  I also tried transposing the 3-d array
> but that didn't work either.
> 
> TIA
> 
> Jim
> 
> --
> Dr. Jim Maas
> University of East Anglia
> 
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