[R] splits with 0s in middle columns

[Rui Barradas]

Hello,

Try the following.

A <- c(
"10/20/30",
"40/20",
"60/10/10/5",
"80/10")

fun <- function(X){
     xname <- deparse(substitute(X))
     s <- strsplit(X, "/")
     n <- max(sapply(s, length))
     tmp <- numeric(n)

     f <- function(x){
         x <- as.numeric(x)
         m <- length(x)
         tmp[n] <- x[m]
         tmp[seq_len(m - 1)] <- x[seq_len(m - 1)]
         tmp
     }

     res <- do.call(rbind, lapply(s, f))
     colnames(res) <- paste0(xname, 1:ncol(res))
     data.frame(res)
}
fun(A)

Hope this helps,

Rui Barradas

Em 31-08-2012 17:10, Sapana Lohani escreveu:
> Hi,
>
> A column of my df looks like
>
> A
> 10/20/30
>
> 40/20
> 60/10/10/5
> 80/10
>
> I want to split it such that the last column has the last composition and if there are not enough the middle columns get the 0s. That way my df would look like
>
> A1 A2 A3 A4
> 10 20 0 30
> 40 0 0 20
> 60 10 10 5
> 80 0 0 10
>
> How can I do that ??
>
> 	[[alternative HTML version deleted]]
>
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