[R] apply --> data.frame
David Winsemius
dwinsemius at comcast.net
Thu Aug 30 19:14:34 CEST 2012
On Aug 30, 2012, at 9:44 AM, Sam Steingold wrote:
>> * Sam Steingold <fqf at tah.bet> [2012-08-30 08:56:17 -0400]:
>>
>> Is there a way for an apply-type function to return a data frame?
>> the closest thing I think of is
>>
>> foo <- as.data.frame(t(sapply(...)))
>> names(foo) <- c(....)
>
> alas, this has a problem of creating a "homogeneous" data frame, i.e.,
> all the columns are numbers or characters, because the function passed
> to sapply returns c(....) and
>> c(1,2,"a")
> [1] "1" "2" "a"
>
> e.g.,
> as.data.frame(t(sapply(c("a,1","b,2","c,3"),function (n)
> strsplit(n,",")[[1]])))
> V1 V2
> a,1 a 1
> b,2 b 2
> c,3 c 3
>
> 'data.frame': 3 obs. of 2 variables:
> $ V1: Factor w/ 3 levels "a","b","c": 1 2 3
> ..- attr(*, "names")= chr "a,1" "b,2" "c,3"
> $ V2: Factor w/ 3 levels "1","2","3": 1 2 3
> ..- attr(*, "names")= chr "a,1" "b,2" "c,3"
>
> I wanted the V1 column to be a string, and V2 to be a number.
> (I know stringsAsFactors=FALSE would replace factors with strings,
> but I
> need a string and a number)
>
> I could, of course, do ret$V2 <- as.numeric(ret$V2) but this would
> mean
> a double conversion: from number to string first (by c()) and then
> back.
It is starting as a 'string' ('character' in R parlance) so you will
need to coerce it to "numeric" at some point:
Consider this alternate route:
> do.call(rbind, strsplit(c("a,1","b,2","c,3"), ",") )
[,1] [,2]
[1,] "a" "1"
[2,] "b" "2"
[3,] "c" "3"
> as.data.frame( do.call(rbind, strsplit(c("a,1","b,2","c,3"), ",") ) )
V1 V2
1 a 1
2 b 2
3 c 3
> str( as.data.frame( do.call(rbind, strsplit(c("a,1","b,2","c,3"),
",") ) , stringsAsFactors=FALSE) )
'data.frame': 3 obs. of 2 variables:
$ V1: chr "a" "b" "c"
$ V2: chr "1" "2" "3"
--
David Winsemius, MD
Alameda, CA, USA
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