[R] (no subject)

[Rui Barradas]

Hello,

You must post a data example to get some help. Use

dput( head(tth, 50) )  # paste the output of this in a post

As for the warnings, they are not errors. They are telling you that it 
can't make a replacement. substitute(x) is probably returning NULL and 
the aggregate return value's column names are ill formed, 'count..' 
where it should be 'count.Mins.to.hospital'.

Anyway, post a data example.

Hope this helps,

Rui Barradas

Em 24-08-2012 13:51, Lynn Hutchings escreveu:
> I'm very new to R and just finding my way, so be gentle!
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> I've hit a swift halt doing some summary statistics on a simple continuous data field, divided into two categories. I'm getting the following error message. I am unclear why length(names(tth$Mins.to.hospital)) is zero and how to alter this. This is preventing me from carrying the summary data forward to any further analyses, which I need to create some new variables to account for the missing data points.
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> I'm sure this is a very simple error, and I apologise for asking!
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> Lynn
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> The output is below - I have the epicalc program loaded.
>
>> aggregate(tth$Mins.to.hospital, by=list(DIRECT=tth$JR.1st.hospital))
>   Note:
>        Missing values removed.
>
>    DIRECT count..  sum..    mean.. median..     sd.. min.. max.$
> 1     No      76 202607 2665.8816      630 5297.410   217 26495
> 2    Yes     319  57859  181.3762       70 1314.982     0 23180
> Warning messages:
> 1: In names(y)[length(names(y))] <- paste("count", as.character(substitute(x)),  :
>    number of items to replace is not a multiple of replacement length
> 2: In names(y)[length(names(y))] <- paste(FUN[i], as.character(substitute(x)),  :
>    number of items to replace is not a multiple of replacement length
> 3: In names(y)[length(names(y))] <- paste(FUN[i], as.character(substitute(x)),  :
>    number of items to replace is not a multiple of replacement length
> 4: In names(y)[length(names(y))] <- paste(FUN[i], as.character(substitute(x)),  :
>    number of items to replace is not a multiple of replacement length
> 5: In names(y)[length(names(y))] <- paste(FUN[i], as.character(substitute(x)),  :
>    number of items to replace is not a multiple of replacement length
> 6: In names(y)[length(names(y))] <- paste(FUN[i], as.character(substitute(x)),  :
>    number of items to replace is not a multiple of replacement length
> 7: In names(y)[length(names(y))] <- paste(FUN[i], as.character(substitute(x)),  :
>    number of items to replace is not a multiple of replacement length
>> colnames(tth)
> [1] "Time.to.hospital.arrival.present.only" "Mins.to.hospital"                      "JR.1st.hospital"
>> length(names(tth$Mins.to.hospital))
> [1] 0
>> length(paste("Count", as.character(substitute(tth$JR.1st.hospital))))
> [1] 3
>
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