[R] How to extract from a column in a table?

arun smartpink111 at yahoo.com
Fri Aug 17 03:04:40 CEST 2012


HI,

Slightly different way to do this:

dat1<-readLines(textConnection("Name
Budlamp-Woodcutter Complex - 15 to 60% slope (60/25/15)
Budlamp-Woodcutter Complex - 15 to 60% slope (60/25/15)
Terrarossa-Blacktail-Pyeatt Complex - 1 to 40% slope (40/35/15/10)
Terrarossa-Blacktail-Pyeatt Complex - 1 to 40% slope (40/35/15/10)
"))
dat2<-data.frame(dat1)

dat3<-data.frame(Name=dat2[2:5,],slope=dat2[2:5,],percentage=dat2[2:5,])
dat3$Name<-gsub("(.*Complex)\\s-\\s(.*slope).*(\\(.*\\))","\\1",dat3$Name) 
dat3$slope<-gsub("(.*Complex)\\s-\\s(.*slope).*(\\(.*\\))","\\2",dat3$slope)
dat3$percentage<-gsub("(.*Complex)\\s-\\s(.*slope).*(\\(.*\\))","\\3",dat3$percentage)
 
 dat3
#                                 Name           slope    percentage
#1          Budlamp-Woodcutter Complex 15 to 60% slope    (60/25/15)
#2          Budlamp-Woodcutter Complex 15 to 60% slope    (60/25/15)
#3 Terrarossa-Blacktail-Pyeatt Complex  1 to 40% slope (40/35/15/10)
#4 Terrarossa-Blacktail-Pyeatt Complex  1 to 40% slope (40/35/15/10)
A.K.




________________________________
From: Sapana Lohani <lohani.sapana at ymail.com>
To: arun <smartpink111 at yahoo.com> 
Cc: R help <r-help at r-project.org> 
Sent: Thursday, August 16, 2012 7:08 PM
Subject: Re: [R] How to extract from a column in a table?


Thank you :)



________________________________
From: arun <smartpink111 at yahoo.com>
To: Sapana Lohani <lohani.sapana at ymail.com> 
Cc: R help <r-help at r-project.org> 
Sent: Thursday, August 16, 2012 1:06 PM
Subject: Re: [R] How to extract from a column in a table?

Hi,

Forgot the last part.

colnames(dat3New)<-c("name","slope","percentage")
 dat3New
                                 name           slope    percentage
1          Budlamp-Woodcutter Complex 15 to 60% slope    (60/25/15)
2          Budlamp-Woodcutter Complex 15 to 60% slope    (60/25/15)
3 Terrarossa-Blacktail-Pyeatt Complex  1 to 40% slope (40/35/15/10)
4 Terrarossa-Blacktail-Pyeatt Complex  1 to 40% slope (40/35/15/10)
A.K.



----- Original Message -----
From: Sapana Lohani <lohani.sapana at ymail.com>
To: "r-help at r-project.org" <r-help at r-project.org>
Cc: 
Sent: Thursday, August 16, 2012 2:41 PM
Subject: [R] How to extract from a column in a table?

Hi, 


I have a table in which one column has the name of the objects as shown below.


Name 

Budlamp-Woodcutter Complex - 15 to 60% slope (60/25/15) 
Budlamp-Woodcutter Complex - 15 to 60% slope (60/25/15) 
Terrarossa-Blacktail-Pyeatt Complex - 1 to 40% slope (40/35/15/10) 
Terrarossa-Blacktail-Pyeatt Complex - 1 to 40% slope (40/35/15/10) 

How can I split the single column into three columns like name (Budlamp-Woodcutter Complex), slope (15 to 60% slope) and percentage
(60/25/15)

thanks

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