[R] How can I get the Ids with Duplicated key and corresponding Ids with original key?

[arun]

Hello,

Not sure if I understand your required output.

Try this:
subset(df,!is.na(match(Reference,Reference[duplicated(Reference)])))
#  Publication Reference Id
#1           1         a  1
#2           2         b  2
#3           3         c  3
#4           1         a  4
#7           2         b  7
#8           3         c  8
A.K.




----- Original Message -----
From: Sri krishna Devarayalu Balanagu <balanagudevarayulu at gvkbio.com>
To: "r-help at r-project.org" <r-help at r-project.org>
Cc: 
Sent: Monday, August 13, 2012 5:17 AM
Subject: [R] How can I get the Ids with Duplicated key and corresponding Ids with original key?


In this following example Id 4 is duplicated with Id 1.
Like this I want both Ids (Duplicated and Duplicated with). Can anyone help?

df <- data.frame(
    "Publication" = c(1, 2, 3, 1, 4, 5, 2, 3),
    "Reference"   = c("a", "b", "c", "a", "d", "e", "b", "c"),
    "Id"= c(1, 2, 3, 4, 5, 6, 7, 8)
                 )

key <- paste(df$Publication, df$Reference, sep="_")
df.key <- cbind(key, df)
Duplicated.ids <- df.key[duplicated(df.key$key), c("Id")]


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