[R] Splitting Data Into Different Series

[Henrique Andrade]

Dear Rui and Arun,

Thanks a lot for your help. I will test all the proposed solutions ;-)

Best regards,
Henrique Andrade

2012/8/6 Rui Barradas <ruipbarradas em sapo.pt>:
> Hello,
>
> Try the following.
>
> split(data.frame(dados), dados[, "code"])
>
> Also, it's better to have data like 'dados' in a data.frame, like this you
> would have dates of class Date, and numbers of classes numeric or integer:
>
>
> dados2 <- data.frame(dados)
> dados2$date <- as.Date(dados2$date)
> dados2$value <- as.numeric(dados2$value)
> dados2$code <- as.integer(dados2$code)
>
> #See the STRucture
> str(dados2)
>
> The code above would be simplified to split(dados2, dados2$code)
>
> And it's also better to keep the result in a list, they are all in one place
> and you can access the components as
>
> result[[ "433" ]]  # etc.
>
> Hope this helps
>
> Rui Barradas
>
> Em 06-08-2012 18:06, Henrique Andrade escreveu:
>>
>> Dear R Community,
>>
>> I'm trying to write a loop to split my data into different series. I
>> need to make a
>> new matrix (or series) according to the series code.
>>
>> For instance, every time the "code" column assumes the value "433" I need
>> to
>> save "date", "value", and "code" into the "dados433" matrix.
>>
>> Please take a look at the following example:
>>
>> dados <-
>> matrix(c("2012-01-01","2012-02-01","2012-03-01","2012-04-01","2012-05-01","2012-06-01",
>>
>>
>> "2012-01-01","2012-02-01","2012-03-01","2012-04-01","2012-05-01","2012-06-01",
>>
>>
>> "2012-01-01","2012-02-01","2012-03-01","2012-04-01","2012-05-01","2012-06-01",
>>
>> 0.56,0.45,0.21,0.64,0.36,0.08,152136,153081,155872,158356,162157,166226,
>>
>>
>> 33.47,34.48,35.24,38.42,35.33,34.43,433,433,433,433,433,433,2005,2005,2005,
>>                          2005,2005,2005,3939,3939,3939,3939,3939,3939),
>> nrow=18, ncol=3, byrow=FALSE,
>>
>> dimnames=list(c(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18),
>>                          c("date", "value", "code")))
>>
>> dados433 <- matrix(data = NA, nrow = 6, ncol = 3, byrow= FALSE)
>> dados2005 <- matrix(data = NA, nrow = 6, ncol = 3, byrow= FALSE)
>> dados3939 <- matrix(data = NA, nrow = 6, ncol = 3, byrow= FALSE)
>>
>> for(i in seq(along=dados[,3])) {
>>      if(dados[i,3] == 433) {dados433[i,1:3] <- dados[i,1:3]}
>> }
>>
>> for(i in seq(along=dados[,3])) {
>>      if(dados[i,3] == 2005) {dados2005[i,1:3] <- dados[i,1:3]}
>> }
>>
>> for(i in seq(along=dados[,3])) {
>>      if(dados[i,3] == 3939) {dados3939[i,1:3] <- dados[i,1:3]}
>> }
>>
>> Best regards,
>> Henrique Andrade
>>
>> ______________________________________________
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>> and provide commented, minimal, self-contained, reproducible code.
>
>



-- 
Henrique Andrade