[R] problem in matching numbers in two variables

John Kane jrkrideau at inbox.com
Sat Apr 28 18:59:53 CEST 2012


I think this works bu there probably is a better way.

xy  <- x %% y

which(xy != 0)


John Kane
Kingston ON Canada


> -----Original Message-----
> From: sagarnikam123 at gmail.com
> Sent: Sat, 28 Apr 2012 08:28:39 -0700 (PDT)
> To: r-help at r-project.org
> Subject: [R] problem in matching numbers in two variables
> 
> i want to compare two variables (having numbers) serially for
> matching/dismatching
> both having equal length
> 
>> x
>   [1] 2 2 1 2 3 2 2 2 2 3 3 2 2 2 2 2 2 3 2 2 2 2 2 2 2 2 2 2 3 2 3 2 2 2
> 1
> 2 2
>  [38] 2 2 2 3 2 3 2 2 1 2 2 2 2 1 1 1 3 2 2 2 2 1 1 3 1 1 1 2 2 2 3 2 3 3
> 3
> 2 2
>  [75] 2 2 3 2 2 1 1 1 2 3 2 2 2 2 2 2 2 2 2 1 1 3 2 2 2 2 2 2 2 2 2 2 2 1
> 3
>> y
>   [1] 2 2 2 1 3 1 3 2 1 3 3 3 3 2 2 1 2 3 3 3 1 1 2 2 2 2 2 2 1 2 3 1 2 2
> 1
> 1 2
>  [38] 1 2 3 2 1 3 1 1 2 2 2 2 1 2 1 2 3 2 3 2 1 2 2 3 1 1 1 2 2 2 3 2 3 3
> 3
> 3 3
>  [75] 2 2 1 2 1 2 1 2 1 3 3 3 1 2 2 2 1 2 1 2 2 3 2 3 2 3 2 2 2 2 1 2 2 2
> 3
>> length(x)
> [1] 109
>> length(y)
> [1] 109
>> #both having equal length
>> which(x%in%y)  #gives no of matches positions
>   [1]   1   2   3   4   5   6   7   8   9  10  11  12  13  14  15  16  17
> 18
>  [19]  19  20  21  22  23  24  25  26  27  28  29  30  31  32  33  34  35
> 36
>  [37]  37  38  39  40  41  42  43  44  45  46  47  48  49  50  51  52  53
> 54
>  [55]  55  56  57  58  59  60  61  62  63  64  65  66  67  68  69  70  71
> 72
>  [73]  73  74  75  76  77  78  79  80  81  82  83  84  85  86  87  88  89
> 90
>  [91]  91  92  93  94  95  96  97  98  99 100 101 102 103 104 105 106 107
> 108
> [109] 109
>> length(which(x%in%y))
> [1] 109
> 
> it show that all numbers are matched ,but in real this is not true
> so,how to find matched numbers from two variables(numeric) like this?
> 
> --
> View this message in context:
> http://r.789695.n4.nabble.com/problem-in-matching-numbers-in-two-variables-tp4594912p4594912.html
> Sent from the R help mailing list archive at Nabble.com.
> 
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