[R] interpolation issue

[R. Michael Weylandt]

Your problem is that length(x) != length(y)

approx uses linear interpolation but there's no way to make sense of
that if you can't match up the x and y coordinates -- and you can't
match up the x and y coordinates if there aren't the same number of
them.

Michael

On Wed, Apr 18, 2012 at 10:15 AM, uday <uday_143_4u at hotmail.com> wrote:
> hi Petr ,
> Thanks for replay and sorry for typo mistake
> approx(pres, sci.pre)  its nothing but approx(pre2, pre1).
>
> so for more simplicity
> x <- c(10.34615 , 52.02116, 146.17357, 243.28644, 347.41504, 431.67105,
>             521.42712, 629.00446 ,729.95941, 827.86279, 921.55078,
> 956.44446)
> y <- c( 983.4477692, 973.6199013, 958.0722141, 938.8194208 ,915.1833983,
> 852.1671089,
>             765.0037479,654.0372907, 526.7369169, 397.0581990, 279.9788079,
> 229.5127059,
>             185.2578164 ,147.2534510,115.1949457,  88.5712513,  66.7337287,
> 49.0140828,
>             23.3535195 ,  0.6609724)
> approx(x,y,xout=x,method="linear")
> still I get error message
> Error in xy.coords(x, y) : 'x' and 'y' lengths differ
>
> I saw the approx. function , but yet I do not know that how we can use that
> for the data set which having different length
>
> So I hope that my problem is bit more clear than before
>
> Cheers
> Uday
>
>
>
>
> --
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