[R] reading a dense file of binary number
David L Carlson
dcarlson at tamu.edu
Tue Oct 18 23:10:51 CEST 2011
Or do you want each number separated?
> data <- textConnection("010101001110101
+ 101010010111110
+ 010010100100000"
+ )
> result <- as.matrix(read.fwf(data, rep(1, 15)))
> result
V1 V2 V3 V4 V5 V6 V7 V8 V9 V10 V11 V12 V13 V14 V15
[1,] 0 1 0 1 0 1 0 0 1 1 1 0 1 0 1
[2,] 1 0 1 0 1 0 0 1 0 1 1 1 1 1 0
[3,] 0 1 0 0 1 0 1 0 0 1 0 0 0 0 0
-----Original Message-----
From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org] On
Behalf Of Jorge I Velez
Sent: Tuesday, October 18, 2011 2:15 PM
To: Brian Tsai
Cc: r-help at r-project.org
Subject: Re: [R] reading a dense file of binary number
Hi Brian,
Take a look at ?scan
> x <- scan(file.choose(), what = 'list')
Read 3 items
> x
[1] "010101001110101" "101010010111110" "010010100100000"
> as.matrix(x)
[,1]
[1,] "010101001110101"
[2,] "101010010111110"
[3,] "010010100100000"
HTH,
Jorge
On Tue, Oct 18, 2011 at 3:09 PM, Brian Tsai <> wrote:
> hi all,
>
> i have a file of the following format that i want to read into a matrix:
>
> 010101001110101
> 101010010111110
> 010010100100000
> ...
>
> it has no headers or row names.
>
> I tried to use read.table(), but it doesn't allow me to specify nothing as
> the column separator (specifying sep='' means whitespace for that
> function). read.fwf doesn't seem appropriate either.
>
> [[alternative HTML version deleted]]
>
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