[R] new standardised variable based on group membership

[John.Morrongiello at csiro.au]

That works a treat Thierry, thanks! I wasn't aware of the plyr package but I like what it does- I'll put it to use work in the future.

Regards

John 

-----Original Message-----
From: ONKELINX, Thierry [mailto:Thierry.ONKELINX at inbo.be] 
Sent: Monday, 3 October 2011 6:36 PM
To: Morrongiello, John (CMAR, Hobart); r-help at r-project.org
Subject: RE: [R] new standardised variable based on group membership

Dear John,

You need to combine scale with a grouping function.

data(Orange)
library(plyr)
Orange <- ddply(Orange, .(Tree), function(x){
	x$ddplyAge <- scale(x$age)[, 1]
	x
})

Orange$aveAge <- ave(Orange$age, by = Orange$Tree, FUN = scale)

all.equal(Orange$ddplyAge, Orange$aveAge)

Best regards,

Thierry


> -----Oorspronkelijk bericht-----
> Van: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org]
> Namens John.Morrongiello at csiro.au
> Verzonden: maandag 3 oktober 2011 7:34
> Aan: r-help at r-project.org
> Onderwerp: [R] new standardised variable based on group membership
> 
> Hi
> I have a data comprised of repeated measures of growth (5-15 records per
> individual) for 580 fish (similar to Orange dataset from nlme library). I would like
> to standardise these growth measures (yi – ŷ/sd) using mean and standard
> deviation unique to each fish. Can someone suggest a function that would help
> me do this? I’ve had a look at scale and sweep but can’t find a worked example
> that does what I’m after
> 
> Cheers
> 
> John
> 
> 
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