[R] function recode within sapply

[Joshua Wiley]

Hi Lara,

Use lapply here instead of sapply or specify simplify = FALSE.  See
?sapply for details.

d[, c("fac1", "fac2")] <- lapply(d[, c("fac1", "fac2")], recode,
"c('A', 'B') = 'XX'", as.factor.result = TRUE)
d[, "fac3"] <- recode(d[, "fac3"], "c('A', 'B') = 'XX'")
str(d)

Cheers,

Josh

On Sun, Oct 2, 2011 at 10:16 PM, Lara Poplarski <larapoplarski at gmail.com> wrote:
> Dear List,
>
> I am using function recode, from package car, within sapply, as follows:
>
> L3 <- LETTERS[1:3]
> (d <- data.frame(cbind(x = 1, y = 1:10), fac1 = sample(L3, 10,
> replace=TRUE), fac2 = sample(L3, 10, replace=TRUE), fac3 = sample(L3,
> 10, replace=TRUE)))
> str(d)
>
> d[, c("fac1", "fac2")] <- sapply(d[, c("fac1", "fac2")], recode,
> "c('A', 'B') = 'XX'", as.factor.result = TRUE)
> d[, "fac3"] <- recode(d[, "fac3"], "c('A', 'B') = 'XX'")
> str(d)
>
> However, the class of columns fac1 and fac2 is "character" as opposed
> to "factor", even though I specify the option "as.factor.result =
> TRUE"; this option works fine with a single column.
>
> Any thoughts?
>
> Many thanks,
> Lara
>
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-- 
Joshua Wiley
Ph.D. Student, Health Psychology
Programmer Analyst II, ATS Statistical Consulting Group
University of California, Los Angeles
https://joshuawiley.com/