[R] help in fitted values in lm function
Timothy Bates
timothy.c.bates at gmail.com
Mon Nov 14 17:00:18 CET 2011
This caught me learning R, and no doubt thousands of others.
When would one ever want the results of fitted() or residuals() to NOT match the data frame rows which went into the model? Certainly making shrinking the results the default is not what 99% of user will want if they need to access residuals: They will want a list of residuals padded with NAs to plot or use in further analyses in the originating data frame.
IMHO, the default na.action for lm() should be “na.exclude" (which, believe it or not, INcludes NAs in the results…)
Best, tim
On 14 Nov 2011, at 3:49 PM, William Dunlap wrote:
> If you want fitted() to return NAs in the positions where
> there were NA's in data, use na.action=na.exclude in your
> call to lm(). E.g.,
>
>> z <- data.frame(y=1:5, x=c(1,NA,3,3,5))
>> fitted(lm(y~x, data=z))
> 1 3 4 5
> 1.25 3.25 3.25 5.25
>> fitted(lm(y~x, data=z, na.action=na.exclude))
> 1 2 3 4 5
> 1.25 NA 3.25 3.25 5.25
>
> I think the help file for model.matrix has more detail,
> including how to use options() to set the na.action for
> your R session.
>
> Bill Dunlap
> Spotfire, TIBCO Software
> wdunlap tibco.com
>
>> -----Original Message-----
>> From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org] On Behalf Of arunkumar1111
>> Sent: Monday, November 14, 2011 3:36 AM
>> To: r-help at r-project.org
>> Subject: Re: [R] help in fitted values in lm function
>>
>> Yes there are few NA in the Data
>>
>> --
>> View this message in context: http://r.789695.n4.nabble.com/help-in-fitted-values-in-lm-function-
>> tp4038642p4039207.html
>> Sent from the R help mailing list archive at Nabble.com.
>>
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