[R] How to alter circle size

[Deepayan Sarkar]

On Mon, May 9, 2011 at 8:23 PM, Dat Mai <dat.d.mai at gmail.com> wrote:
> Thanks for the help! Though, when I do this, I get a message saying "Error
> using packet 1 value where TRUE/FALSE." Would that have anything to do with
> this set of code?

It might. (As we don't know what you "did", we can't really say.)

> On Sun, May 8, 2011 at 3:00 PM, Deepayan Sarkar <deepayan.sarkar at gmail.com>
> wrote:
>>
>> On Fri, May 6, 2011 at 10:21 PM, Dat Mai <dat.d.mai at gmail.com> wrote:
>> > Hello all,
>> >
>> > I'm trying  to create a heatmap using 2 matrices I have: z and v. Both
>> > matrices represent different correlations for the same independent
>> > variables. The problem I have is that I wish to have the values from
>> > matrix
>> > z to be represented by color intensity while having the values from
>> > matrix v
>> > to be represented by circle size. I currently have the following in
>> > front of
>> > me and an unsure of what to add or change in order to achieve that goal.
>> >
>> > panel.corrgram.2 =
>> > function(x, y, z, subscripts, at = pretty(z), scale = 0.8, ...)
>> > {
>> >  require("grid", quietly = TRUE)
>> >  x <- as.numeric(x)[subscripts]
>> >  y <- as.numeric(y)[subscripts]
>> >  z <- as.numeric(z)[subscripts]
>> >  zcol <- level.colors(z, at = at, ...)
>> >  for (i in seq(along = z))
>> >  {
>> >    lims <- range(0, z[i])
>> >    tval <- 2 * base::pi * seq(from = lims[1], to = lims[2], by = 0.01)
>> >    grid.polygon(x = x[i] + .5 * scale * c(0, sin(tval)),
>> >      y = y[i] + .5 * scale * c(0, cos(tval)),
>> >      default.units = "native",
>> >      gp = gpar(fill = zcol[i]))
>> >    grid.circle(x = x[i], y = y[i], r = .5 * scale,
>> >      default.units = "native")
>> >  }
>> > }
>>
>> Probably this modification
>>
>> panel.corrgram.2 <-
>>    function(x, y, z, v, subscripts, at = pretty(v), scale = 0.8, ...)
>> {
>>    require("grid", quietly = TRUE)
>>    x <- as.numeric(x)[subscripts]
>>    y <- as.numeric(y)[subscripts]
>>    z <- as.numeric(z)[subscripts]
>>    zcol <- level.colors(v, at = at, ...)
>>
>>    <Rest unchanged>
>>
>>
>> followed by
>>
>> levelplot(signif(z,3), v = v, panel = panel.corrgram.2, ...)
>>
>> will do it.
>>
>> -Deepayan
>>
>>
>> >
>> > k=levelplot(signif(z,3), scales = list(x = list(rot = 45)),
>> > col.regions=col.sch, panel = panel.corrgram.2,
>> > label = num.circ, xlab="", ylab="", main=paste(output,"receptor
>> > response"))
>> > print(k)
>> >
>> > --
>> > Best,
>> > Dat Mai
>> > PhD Rotation Student
>> > Albert Einstein College of Medicine
>> >
>> >        [[alternative HTML version deleted]]
>> >
>> > ______________________________________________
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