[R] Creating binary variable depending on strings of two dataframes
Pete Pete
noxyport at gmail.com
Fri May 6 17:35:02 CEST 2011
Gabor Grothendieck wrote:
>
> On Tue, Dec 7, 2010 at 11:30 AM, Pete Pete <noxyport at gmail.com>
> wrote:
>>
>> Hi,
>> consider the following two dataframes:
>> x1=c("232","3454","3455","342","13")
>> x2=c("1","1","1","0","0")
>> data1=data.frame(x1,x2)
>>
>> y1=c("232","232","3454","3454","3455","342","13","13","13","13")
>> y2=c("E1","F3","F5","E1","E2","H4","F8","G3","E1","H2")
>> data2=data.frame(y1,y2)
>>
>> I need a new column in dataframe data1 (x3), which is either 0 or 1
>> depending if the value "E1" in y2 of data2 is true while x1=y1. The
>> result
>> of data1 should look like this:
>> x1 x2 x3
>> 1 232 1 1
>> 2 3454 1 1
>> 3 3455 1 0
>> 4 342 0 0
>> 5 13 0 1
>>
>> I think a SQL command could help me but I am too inexperienced with it to
>> get there.
>>
>
> Try this:
>
>> library(sqldf)
>> sqldf("select x1, x2, max(y2 = 'E1') x3 from data1 d1 left join data2 d2
>> on (x1 = y1) group by x1, x2 order by d1.rowid")
> x1 x2 x3
> 1 232 1 1
> 2 3454 1 1
> 3 3455 1 0
> 4 342 0 0
> 5 13 0 1
>
>
> --
> Statistics & Software Consulting
> GKX Group, GKX Associates Inc.
> tel: 1-877-GKX-GROUP
> email: ggrothendieck at gmail.com
>
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>
That works pretty cool but I need to automate this a bit more. Consider the
following example:
list1=c("A01","B04","A64","G84","F19")
x1=c("232","3454","3455","342","13")
x2=c("1","1","1","0","0")
data1=data.frame(x1,x2)
y1=c("232","232","3454","3454","3455","342","13","13","13","13")
y2=c("E13","B04","F19","A64","E22","H44","F68","G84","F19","A01")
data2=data.frame(y1,y2)
I want now to creat a loop, which creates for every value in list1 a new
binary variable in data1. Result should look like:
x1 x2 A01 B04 A64 G84 F19
232 1 0 1 0 0 0
3454 1 0 0 1 0 1
3455 1 0 0 0 0 0
342 0 0 0 0 0 0
13 0 1 0 0 1 1
Thanks!
--
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