[R] Str info. Thanks for helping

[Ivan Calandra]

It looks from str(SA) that Response IPS1 is a data.frame of class "anova", which probably cannot be coerced to vector.

Maybe you can use unlist() instead of as.vector()
Or something like 
SA[["Response IPS1"]]["as.factor(WSD)",]  ## to select the first row only, even maybe with unlist()

Without a better REPRODUCIBLE example, I cannot tell more (maybe some others can, that's why I reply to the list)

HTH,
Ivan


Le 4 mai 2011 à 20:17, reith_william at bah.com a écrit :

> I am still waiting for this to get posted so I thought I would email it to you.
> 
> SA gives the output: 
> 
> Response IPS1 : 
>                Df Sum Sq Mean Sq F value   Pr(>F)     
> as.factor(WSD)   3 3.3136 1.10455  23.047 5.19e-12 *** 
> Residuals      129 6.1823 0.04793                     
> --- 
> Signif. codes:  0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1 
> . 
> . 
> . 
> There are 11 more just like this output. Just increment IPS1 to IPS2, etc. 
> 
> 
> Goal: save "3 3.3136 1.10455  23.047 5.19e-12" as a vector. 
> 
> 
> Str(SA) gives the output: 
> 
> str(SA) 
>> str(SA) 
> List of 12 
> " $  Response IPS1 :Classes 'anova' and 'data.frame': 2 obs. of  5 variables:" 
>  ..$ Df     : num [1:2] 3 129 
>  ..$ Sum Sq : num [1:2] 3.31 6.18 
>  ..$ Mean Sq: num [1:2] 1.1045 0.0479 
>  ..$ F value: num [1:2] 23 NA 
>  ..$ Pr(>F) : num [1:2] 5.19e-12 NA 
> 
> 
> There are several more but they are just repeats of this one only with IPS2, IPS3,...  
> 
> The command: 
> 
>> SA1<-as.vector(SA$"Reponse IPS1") 
> 
> Returns 
> 
>> NULL 
> 
> As do several variations I have tried. Any ideas.



--
Ivan CALANDRA
PhD Student
University of Hamburg
Biozentrum Grindel und Zoologisches Institut und Museum
Abt. Säugetiere
Martin-Luther-King-Platz 3
D-20146 Hamburg, GERMANY
+49(0)40 42838 6231
ivan.calandra at uni-hamburg.de

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