[R] help please: put output into dataframe

Fri Mar 18 15:04:08 CET 2011

I think it was suggested that you save your output to a 'list' and
then you will have it in a format that can accept variable numbers of
items in each element and it is also in a form that you can easily
process it to create whatever other output you might need.

On Fri, Mar 18, 2011 at 7:24 AM, Ram H. Sharma <sharma.ram.h at gmail.com> wrote:
> Hi Dennis and R-users
>
> Thank you for more help. I am pretty close, but challenge still remain is
> forcing the output with different length to output dataframe.
>
>> x <- data.frame(apply(datafr1, 2, fout))
> Error in data.frame(var1 = c(-0.70777998321315, 0.418602152926712,
> 2.08356737154810,  :
>  arguments imply differing number of rows: 28, 12, 20, 19
>
> As I need to work with >2000 variables, my intension here is to save this
> output to such way that it would be further manipulated. Topline is to save
> in dataframe that have extreme values for the variable concerned and
> bottomline is automate to save the output printed in the screen to a
> textfile.
>
> Thank you for help once again.
>
> Ram
>
>
> On Fri, Mar 18, 2011 at 3:16 AM, Dennis Murphy <djmuser at gmail.com> wrote:
>
>> Hi:
>>
>> Is this what you're after?
>>
>> fout <- function(x) {
>>      lim <- median(x) + c(-2, 2) * mad(x)
>>      x[x < lim[1] | x > lim[2]]
>>    }
>> > apply(datafr1, 2, fout)
>> $var1
>>  [1] 17.5462078 18.4548214  0.7083442  1.9207578 -1.2296787 17.4948240
>>  [7] 19.5702558  1.6181150 20.9791652 -1.3542099  1.8215087 -1.0296303
>> [13] 20.5237930 17.5366497 18.5657566  0.9335419 19.7519983 17.8607968
>> [19] 19.1307524 19.6145711 21.8037136 19.1532175 -2.6688409 19.6949309
>> [25] 1.9712347
>>
>> $var2
>>  [1]  37.3822087  35.6490641  35.6000785  38.5981086  -1.6504275
>> 37.1419290
>>  [7]  37.7605230  40.3508689   0.6639900   2.4695841  38.8209491
>> 39.9087921
>> [13]  38.9907585  35.8279437   2.7870799  37.0941113   0.6308583
>> 36.4556638
>> [19] -10.2384849   2.8480199  -7.7680457  35.7076539  -0.5467739
>> 3.4702765
>> [25]  40.4818580   3.2864273   1.4917174
>>
>> $var3
>>  [1]  74.252563  68.396391  68.845461  -5.006545  66.083402  76.036577
>>  [7]  75.112586  -6.374241  63.883549  64.041216 -19.764360 -15.051017
>> [13]  -9.782767  64.696013  70.970648  -4.562031 -22.135003  70.549310
>> [19]  69.495915  -4.095587  86.612375  87.029526  70.072126  -6.421695
>> [25] 65.737536
>>
>> $var4
>>  [1]  81.476483  87.098767 -10.451616  91.927329  86.588952  85.080950
>>  [7]  84.958645  -9.456368  86.270876 -22.936779  83.314032
>>
>> Double checks:
>> > apply(datafr1, 2, function(x) median(x) + c(-2, 2) * mad(x))
>>          var1      var2      var3      var4
>> [1,]  2.12167  3.779415 -3.736066 -3.471752
>> [2,] 17.37176 34.929800 62.969733 80.224799
>> > apply(datafr1, 2, range)
>>           var1      var2      var3      var4
>> [1,] -2.668841 -10.23848 -22.13500 -22.93678
>> [2,] 21.803714  40.48186  87.02953  91.92733
>>
>> Assuming you wanted to do this columnwise (by variable), it appears to be
>> doing the right thing.
>>
>> HTH,
>> Dennis
>>
>>
>> On Thu, Mar 17, 2011 at 7:04 PM, Ram H. Sharma <sharma.ram.h at gmail.com>wrote:
>>
>>> Dear R community members
>>>
>>> I have been struggling on this simple question, but never get appropriate
>>> solution. So please help.
>>>
>>>  # my data, though I have a large number of variables
>>> var1 <- rnorm(500, 10,4)
>>> var2 <- rnorm(500, 20, 8)
>>> var3 <- rnorm(500, 30, 18)
>>> var4 <- rnorm(500, 40, 20)
>>> datafr1 <- data.frame(var1, var2, var3, var4)
>>>
>>> # my unsuccessful codes
>>>  nvar <- ncol(datafr1)
>>> for (i in 1:nvar) {
>>>              out1 <- NULL
>>>              out2 <- NULL
>>>              medianx <- median(getdata[,i], na.rm = TRUE)
>>>              show(madx <- mad(getdata[,i], na.rm = TRUE))
>>>              MD1 <- c(medianx + 2*madx)
>>>              MD2 <- c(medianx - 2*madx)
>>>              out1[i] <- which(getdata[,i] > MD1) # store data that are
>>> greater than median + 2 mad
>>>              out2[i] <- which (getdata[,1] < MD2) # store data that are
>>> greater than median - 2 mad
>>>             resultdf <- data.frame(out1, out2)
>>>             write.table (resultdf, "out.csv", sep=",")
>>>              }
>>>
>>>
>>> My idea here is to store those value which are either greater than median
>>> +
>>> 2 *MAD or less than median - 2*MAD. Each variable have different length of
>>> output.
>>>
>>> The following last error message:
>>> Error in data.frame(out1, out2) :
>>>  arguments imply differing number of rows: 2, 0
>>> In addition: Warning messages:
>>> 1: In out1[i] <- which(getdata[, i] > MD1) :
>>>  number of items to replace is not a multiple of replacement length
>>> 2: In out2[i] <- which(getdata[, 1] < MD2) :
>>>  number of items to replace is not a multiple of replacement length
>>> 3: In out1[i] <- which(getdata[, i] > MD1) :
>>>  number of items to replace is not a multiple of replacement length
>>>
>>> Thank you in advance for helping me.
>>>
>>> Best regards;
>>> RHS
>>>
>>>        [[alternative HTML version deleted]]
>>>
>>> ______________________________________________
>>> R-help at r-project.org mailing list
>>> https://stat.ethz.ch/mailman/listinfo/r-help
>>> PLEASE do read the posting guide
>>> http://www.R-project.org/posting-guide.html
>>> and provide commented, minimal, self-contained, reproducible code.
>>>
>>
>>
>
>        [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>

-- 
Jim Holtman
Data Munger Guru

What is the problem that you are trying to solve?