[R] Refine ARMA model
Prof Brian Ripley
ripley at stats.ox.ac.uk
Wed Mar 2 15:59:27 CET 2011
Hint: the 'fixed' argument can be used to set a parameter to a fixed
value such as zero.
With the reproducible example we asked you for, we might have shown
you how to use it ....
On Wed, 2 Mar 2011, Chuse chuse wrote:
> Dear users,
>
> I tried to fit an AR(2) model to data. This the result:
>> arima(vw,c(3,0,0))
>
> Call:
> arima(x = vw, order = c(3, 0, 0))
>
> Coefficients:
> ar1 ar2 ar3 intercept
> 0.1052 -0.0102 -0.1203 0.0099
> s.e. 0.0337 0.0339 0.0338 0.0018
>
> sigma^2 estimated as 0.002934: log likelihood = 1293.16, aic = -2576.33
>
> Now, ar2 is not significantly different from zero.
> I would like to refine the model considering ar1 and ar3 only so I fit a model
> x[t]=c+m*x[t-1] + n*x[t-3].
>
> Anyone could help me and tell me how to do it? Thank you very much.
> Chuse
--
Brian D. Ripley, ripley at stats.ox.ac.uk
Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel: +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UK Fax: +44 1865 272595
More information about the R-help
mailing list