[R] Vector with factors inside lists/tuples

[Håvard Wahl Kongsgård]

>> glm( V0 ~ "HARRY"  + "KLINE" + "Brown" + "Larry")
>
> No. You are mistaken. Assuming that V0 is defined and has the same length as
> there are rows in that data.frame, then V1 and V2 would be the arguments in
> the formula and they would not be quoted.
>
> ?glm   # and work through the examples

With the example I meant that the factors in the vector V1 and V2
would be treated like individual binary/dummy variables.

Back to my real question; Is there no other way to do this in R???


2011/6/25 David Winsemius <dwinsemius at comcast.net>:
>
> On Jun 25, 2011, at 2:13 PM, Håvard Wahl Kongsgård wrote:
>
>> Hi, sorry my question was not really clear
>>
>>  |Are you very early in efforts at learning R?
>> No, have been a long term user of R, but only use R for the statistical
>> stuff.
>>
>> The heart of the issue is that I have list of keywords that I want to
>> analyse with a machine learning algorithm (20 000 keywords with a
>> response variables). It's much like "micro" array data, but in my case
>> it's not "genes", but instead keywords. To get it to work in R, I
>> could create a data frame with multiple vectors containing different
>> factors.
>> That would look like this
>> V1, V2,
>> "Harry", "Kline"
>> "Brown", "Larry"
>>
>> If I am not mistaken if I used V1 and V2 with the standard GLM
>> function the result would be like
>>
>> glm( V0 ~ "HARRY"  + "KLINE" + "Brown" + "Larry")
>
> No. You are mistaken. Assuming that V0 is defined and has the same length as
> there are rows in that data.frame, then V1 and V2 would be the arguments in
> the formula and they would not be quoted.
>
> ?glm   # and work through the examples
>
>>
>> Or I could create a complex ordered array where keywords are
>> represented 1 and 0.
>> If I used that in GLM I would get the same result with glm?
>>
>> But is there a better approach?
>>
>> -Håvard
>
> David Winsemius, MD
> West Hartford, CT
>
>



-- 
Håvard Wahl Kongsgård

http://havard.security-review.net/