[R] automatically generate the output name of my "for" loops

jim holtman jholtman at gmail.com
Mon Jun 13 17:50:47 CEST 2011


I think you need '[['

group[[i]] <- which(k1$cluster == i)

On Mon, Jun 13, 2011 at 11:35 AM, jiliguala <jiliguala at mail.com> wrote:
> really thanks for helping.
>
> i just did just like what Petr Pikal said,
> but it appeared some error like this:
>
> There were 50 or more warnings (use warnings() to see the first 50):
>
> Warning messages:
> 1: In group[i] <- which(k1$cluster == i) :
>  number of items to replace is not a multiple of replacement length
> 2: In group[i] <- which(k1$cluster == i) :
>  number of items to replace is not a multiple of replacement length
> 3: In group[i] <- which(k1$cluster == i) :
>  number of items to replace is not a multiple of replacement length
> ...
> ...
> ...
>
> and some solution for that, thanks..
>
> --
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>
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-- 
Jim Holtman
Data Munger Guru

What is the problem that you are trying to solve?



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