[R] assign a cluster based on a variable

[Dominik P.H. Kalisch]

Hi Uwe,

thanks for your help. I didn't know that function (mea culpa)...
With merge() it works what I want to do.
But I'm still interessted, for a learning purpose, why the loop didn't
work. So here are the str() results:

> str(cluster)
 int [1:18, 1:2] 12051000 12052000 12053000 12054000 12060000 12061000
12062000 12063000 12064000 12065000 ...
 - attr(*, "dimnames")=List of 2
  ..$ : chr [1:18] "1" "2" "3" "4" ...
  ..$ : chr [1:2] "Kreis" "Cluster"

> str(KreisSA)
 num [1:2302, 1:2] 12069000 12072000 12067000 12060000 12070000 ...
 - attr(*, "dimnames")=List of 2
  ..$ : NULL
  ..$ : chr [1:2] "Kreis" "Cluster"

Thanks for your help.


On Tue, 07 Jun 2011 22:49:04 +0200, Uwe Ligges
<ligges at statistik.tu-dortmund.de> wrote:
> On 07.06.2011 16:24, Dominik P.H. Kalisch wrote:
>> Hi,
>>
>> I have two matrices of the following form:
>>
>> cluster (n=18):
>> 12062 1
>> 12063 2
>> 12064 2
>> 12065 3
>> 12066 5
>>
>> KreisSA (n=2304)
>> 12062
>> 12062
>> 12067
>> 12065
>> 12063
>> 12067
>>
>> I try to assign the cluster[,2] to KreisSAa by the follwoing loop:
>>
>> n <- nrow(cluster)
>> KreisSAa <- numeric()
>>
>> for(i in 1:n){
>> KreisSAa[KreisSA == cluster[i,1]] <- cluster[i,2]
>> }
>>
>> The result is a vector of the length n=4608 where after the entry 2304
>> are just NA's
>> Has someone an idea what I do wrong?
> 
> Since we do not know the structure of your objects, we cannot say
> easily. You may want to provide
> 
> str(cluster)
> and
> str(KreisSA)
> 
> Anyway: I'd just use merge()
> 
> Uwe Ligges
> 
> 
> 
> 
> 
> 
>> Thanks for your help.
>> Dominik
>>
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