[R] plot + axis: Individually moving tick labels with hadj?

[Marius Hofert]

Hi Sarah,

very nice, thanks!

Cheers,

Marius

On 2011-06-03, at 13:14 , Sarah Goslee wrote:

> Hi Marius,
> 
> I actually prefer the first (default) arrangement, with the labels centered, but
> if you want to align the equals under the tick mark one option is to use
> axis() twice:
> 
> plot(1:5, 5:1, xaxt="n")
> axis(1, at=1:5, labels=c(1,2,"",4,5))
> axis(1, at=3.15, tick=FALSE, labels=expression(3==beta[foooooo]))
> 
> Sarah
> 
> On Fri, Jun 3, 2011 at 7:02 AM, Marius Hofert <m_hofert at web.de> wrote:
>> Dear all,
>> 
>> consider the following plot:
>> 
>> plot(1:5, 5:1, xaxt="n")
>> axis(1, at=1:5, labels=c(1,2,expression(3==beta[foooooo]),4,5))
>> 
>> the label at 3 is not nice, so consider this
>> plot(1:5, 5:1, xaxt="n")
>> axis(1, at=1:5, labels=c(1,2,expression(3==beta[foooooo]),4,5),
>>     padj=c(0,0,0.18,0,0))
>> 
>> Now I tried to move the label horizontally so that the equality sign is
>> vertically aligned with the tick. Since hadj moves all labels, I tried:
>> plot(1:5, 5:1, xaxt="n")
>> axis(1, at=1:5, labels=c(1,2,expression(3==beta[foooooo]),4,5),
>>     hadj=c(0,0,0.22,0,0), padj=c(0,0,0.18,0,0))
>> 
>> Why is it not possible to individually move the labels horizontally?
>> Simply moving all of them does not look very good...
>> plot(1:5, 5:1, xaxt="n")
>> axis(1, at=1:5, labels=c(1,2,expression(3==beta[foooooo]),4,5),
>>     hadj=0.22, padj=c(0,0,0.18,0,0))
>> 
>> Cheers,
>> 
>> Marius
>> 
> 
> 
> -- 
> Sarah Goslee
> http://www.functionaldiversity.org