[R] [solved] scripting/littler: How to call function named iteratively (`f1`, `f2`, …)?
Paul Menzel
paulepanter at users.sourceforge.net
Sat Jul 30 14:56:31 CEST 2011
Am Freitag, den 29.07.2011, 15:28 +0200 schrieb Paul Menzel:
> wanting to compare different implementations of a solution I want to
> script it to iterate over the different implementations. Is there a way
> to do this in the R shell/command line?
>
> $ more /tmp/iterf.r
> f1 <- function(n = 100000,
> l = 100000)
> {
> z = n + l
> }
>
> f2 <- function(n = 100000,
> l = 100000)
> {
> z = 2 * (n + l)
> }
[…]
> Going on I tried to script that using the `r` from the package `littler`
> [1]. Unfortunately because of the required quotes "" for the command
> `source()` I am not able to expand the variable.
>
> $ for i in $(seq 2); do r -e "print($i)" ; done
> [1] 1
> [1] 2
> $ for i in $(seq 2); do r -e 'source("/tmp/iterf.r"); print(1)' ; done
> [1] 1
> [1] 1
> $ # The next example does not work, because the variable $i does not get expanded when surrounded by ''.
> $ for i in $(seq 2); do r -e 'source("/tmp/iterf.r"); print(f$i(2, 3))' ; done
> Fehler in print(f$i(2, 3)) : Objekt 'f' nicht gefunden
> Ausführung angehalten
> Fehler in print(f$i(2, 3)) : Objekt 'f' nicht gefunden
> Ausführung angehalten
>
> Searching for »iterating function names« with rseek.org did give any
> good results. I also read the appendix in the introduction to R [2], but
> this did not have anything regarding to this either.
>
> Is there a way to script this?
Searching for »source code« in the R Wiki, I found the Wiki page
scriptingr [3] – which did not turn up in my other searches. As it
turned out you can encode `"` by `\"` in Bash too. So the following
works just fine.
$ for i in $(seq 2); do r -e "source(\"/tmp/iterf.r\"); print(f$i(2, 3)) )" ; done
[1] 5
[1] 10
Thanks,
Paul
> [1] http://packages.debian.org/sid/littler
> [2] http://cran.r-project.org/doc/manuals/R-intro.html#Scripting-with-R
[3] http://rwiki.sciviews.org/doku.php?id=tips:scriptingr
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