[R] Integration in R
Ravi Varadhan
rvaradhan at jhmi.edu
Mon Jan 10 15:46:15 CET 2011
You are missing basic algebra skills!
You had:
myfunc<- function(x) {0.25*(9*x^4 + 6*x^2 + 1)}
This should be:
myfunc<- function(x) {0.25*(9*x^4 - 6*x^2 + 1)}
Ravi.
-------------------------------------------------------
Ravi Varadhan, Ph.D.
Assistant Professor,
Division of Geriatric Medicine and Gerontology School of Medicine Johns
Hopkins University
Ph. (410) 502-2619
email: rvaradhan at jhmi.edu
-----Original Message-----
From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org] On
Behalf Of Alaios
Sent: Monday, January 10, 2011 9:13 AM
To: r-help at r-project.org
Subject: [R] Integration in R
Dear all,
It has been ages since I studied integration in college. Right now I
try to recover all this kind of knowledge and then try to understand how
integration works.
Thus I am doing some first 'experiments' and I would like to request your
help and comments.
I have the function:
p2<-function(x){0.5*(3*x^2-1)}
# I found the square of p2 by using some pencil and paper.
# The result is inside myfunc below
myfunc<- function(x) {0.25*(9*x^4+6*x^2+1)}
# Below I made R to find the square of p2
p2sq<-function(x) {p2(x) * p2(x)}
# Now I am trying to integrate both two function at the same interval. #Both
functions should denote the square of p2
integrate(p2sq,-1,+1)
# returns 0.4 with absolute error < 4.4e-15
integrate(myfunc,-1,+1)
# returns 2.4 with absolute error < 2.7e-14
if there is no error in my calculations could you please explain me why
the two integrations return different results. Might be that I am
missing something from the theory. I would like to thank you for your
help
Regards
Alex
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