[R] sort a 3 dimensional array across third dimension ?

[rex.dwyer at syngenta.com]

Although I suggested to someone else that for-loops be avoided, they are not in the inner loop in this code, and it's probably easier to understand than some sort of apply:

a = array(round(100*runif(60)),dim=c(3,4,5))
a
for (i in 1:dim(a)[1])
 for (j in 1:dim(a)[2])
  a[i,j,] = sort(a[i,j,])
a

Is that what you want?

-----Original Message-----
From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org] On Behalf Of Maas James Dr (MED)
Sent: Friday, February 18, 2011 8:01 AM
To: r-help at r-project.org
Subject: [R] sort a 3 dimensional array across third dimension ?

I'm attempting to sort a 3 dimensional array that looks like this
> x
, , 1
     [,1] [,2]
[1,]    9    9
[2,]    7    9
, , 2
     [,1] [,2]
[1,]    6    5
[2,]    4    6
, , 3
     [,1] [,2]
[1,]    2    1
[2,]    3    2

Such that it ends up like this ....
> y
, , 1
     [,1] [,2]
[1,]    2    1
[2,]    3    2
, , 2
     [,1] [,2]
[1,]    6    5
[2,]    4    6
, , 3
     [,1] [,2]
[1,]    9    9
[2,]    7    9

I think this is sorting across the third dimension but several attempts using either the sort or apply functions have not worked.  Any and all suggestions most welcome.  Thanks

J

===============================
Dr. Jim Maas
University of East Anglia


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