[R] Help creating a symmetric matrix?

[Matt Considine]

Thank you all for your help and best wishes for the holiday season.
Matt Considine

On 12/24/2011 8:38 AM, William Revelle wrote:
> Dear Matt, Sarah and Rui,
>
> To answer the original question for creating a symmetric matrix
>
>
>>>> v<-c(0.33740, 0.26657, 0.23388, 0.23122, 0.21476, 0.20829, 0.20486,
>>>> 0.19439, 0.19237,
>>>> 0.18633, 0.17298, 0.17174, 0.16822, 0.16480, 0.15027)
>
> z<-diag(6)
> z[row(z)>  col(z)]<- v
> z<- z + t(z)
> diag(z)<- 0
>
>> z
>          [,1]    [,2]    [,3]    [,4]    [,5]    [,6]
> [1,] 0.00000 0.33740 0.26657 0.23388 0.23122 0.21476
> [2,] 0.33740 0.00000 0.20829 0.20486 0.19439 0.19237
> [3,] 0.26657 0.20829 0.00000 0.18633 0.17298 0.17174
> [4,] 0.23388 0.20486 0.18633 0.00000 0.16822 0.16480
> [5,] 0.23122 0.19439 0.17298 0.16822 0.00000 0.15027
> [6,] 0.21476 0.19237 0.17174 0.16480 0.15027 0.00000
>
>
> Bill
>
>
> On Dec 24, 2011, at 6:04 AM, Sarah Goslee wrote:
>
>> Or the slightly shorter:
>>
>> z<-diag(6)
>> z[row(z)>  col(z)]<- v
>>
>> which is what lower.tri() does,
>>
>> and
>> z<- diag(6)
>> z[lower.tri(z)]<- v
>>
>> also works.
>>
>> Sarah
>>
>> On Fri, Dec 23, 2011 at 9:31 PM, Rui Barradas<ruipbarradas at sapo.pt>  wrote:
>>> Matt Considine wrote
>>>> Hi,
>>>> I am trying to work with the output of the MINE analysis routine found at
>>>>     http://www.exploredata.net
>>>>
>>>> Specifically, I am trying to read the results into a matrix (ideally an
>>>> n x n x 6 matrix, but I'll settle right now for getting one column into
>>>> a matrix.)
>>>>
>>>> The problem I have is not knowing how to take what amounts to being one
>>>> half of a symmetric matrix - excluding the diagonal - and getting it
>>>> into a matrix.  I have tried using "lower.tri" as found here
>>>>     https://stat.ethz.ch/pipermail/r-help/2008-September/174516.html
>>>> but it appears to only partially fill in the matrix.  My code and an
>>>> example of the output is below.  Can anyone point me to an example that
>>>> shows how to create a matrix with this sort of input?
>>>>
>>>> Thank you in advance,
>>>> Matt
>>>>
>>>> #v<-newx[,3]
>>>> #or, for the sake of this example
>>>> v<-c(0.33740, 0.26657, 0.23388, 0.23122, 0.21476, 0.20829, 0.20486,
>>>> 0.19439, 0.19237,
>>>> 0.18633, 0.17298, 0.17174, 0.16822, 0.16480, 0.15027)
>>>> z<-diag(6)
>>>> ind<- lower.tri(z)
>>>> z[ind]<- t(v)[ind]
>>>>
>>>> z
>>>>           [,1]    [,2] [,3] [,4] [,5] [,6]
>>>> [1,] 1.00000 0.00000    0    0    0    0
>>>> [2,] 0.26657 1.00000    0    0    0    0
>>>> [3,] 0.23388 0.19237    1    0    0    0
>>>> [4,] 0.23122 0.18633   NA    1    0    0
>>>> [5,] 0.21476 0.17298   NA   NA    1    0
>>>> [6,] 0.20829 0.17174   NA   NA   NA    1
>>>>
>>>>
>>> Hello,
>>>
>>> Aren't you complicating?
>>>
>>> In the last line of your code, why use 'v[ind]' if 'ind' indexes the matrix,
>>> not the vector?
>>>
>>> z<-diag(6)
>>> ind<- lower.tri(z)
>>> z[ind]<- v                        #This works
>>> z
>>>
>>> Rui Barradas
>>>
>> -- 
>> Sarah Goslee
>> http://www.functionaldiversity.org
>>
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>> and provide commented, minimal, self-contained, reproducible code.
>>
> William Revelle		           http://personality-project.org/revelle.html
> Professor			           http://personality-project.org
> Department of Psychology   http://www.wcas.northwestern.edu/psych/
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