[R] find and replace string

[jim holtman]

try this:

> x <- c('sta_+1+0_field2ndtry_0000$01.cfg'
+      , 'sta_+1+0_field2ndtry_0000$01.cfg'
+      , 'sta_+1-0_field2ndtry_0000$01.cfg'
+      , 'sta_+1+0_field2ndtry_0000$01.cfg'
+      )
> # find matching fields
> values <- grep("[^+]*\\+[^+]*\\+0", x, value = TRUE)
> # split into two pieces
> splitValues <- sub("([^+]*\\+[^+]*\\+)0(.*)", "\\1^\\2", values)
> for (i in splitValues){
+     for (j in 0:3){
+         print(sub("\\^", j, i))
+     }
+ }
[1] "sta_+1+0_field2ndtry_0000$01.cfg"
[1] "sta_+1+1_field2ndtry_0000$01.cfg"
[1] "sta_+1+2_field2ndtry_0000$01.cfg"
[1] "sta_+1+3_field2ndtry_0000$01.cfg"
[1] "sta_+1+0_field2ndtry_0000$01.cfg"
[1] "sta_+1+1_field2ndtry_0000$01.cfg"
[1] "sta_+1+2_field2ndtry_0000$01.cfg"
[1] "sta_+1+3_field2ndtry_0000$01.cfg"
[1] "sta_+1+0_field2ndtry_0000$01.cfg"
[1] "sta_+1+1_field2ndtry_0000$01.cfg"
[1] "sta_+1+2_field2ndtry_0000$01.cfg"
[1] "sta_+1+3_field2ndtry_0000$01.cfg"

On Fri, Dec 2, 2011 at 6:30 AM, Alaios <alaios at yahoo.com> wrote:
> Dear all,
> I would like to search in a string for the second occurrence of a symbol and replace the symbol after it
>
> For example my strings look like
>
> sta_+1+0_field2ndtry_0000$01.cfg
>
> I want to find the digit that comes after the second +, in that case is zero
> and then over a loop create the strings below
>
> sta_+1+0_field2ndtry_0000$01.cfg
>
> sta_+1+1_field2ndtry_0000$01.cfg
>
> sta_+1+2_field2ndtry_0000$01.cfg
>
> sta_+1+3_field2ndtry_0000$01.cfg
>
> and so on..
> I have already tried strsplit but this will make things more complex...
>
> Could you please help me with that?
>
> B.R
> Alex
>
>        [[alternative HTML version deleted]]
>
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-- 
Jim Holtman
Data Munger Guru

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