[R] splitting sample names

[Jorge I Velez]

Sorry for the noise.  The code should have been 

sapply(with(xx, strsplit(as.character(Sample), "_")), "[", 2)

instead of what I sent previously.

HTH,
Jorge


On Aug 18, 2011, at 7:30 PM, Jorge I Velez wrote:

> Hi Sharad,
> 
> Try
> 
> xx$newSample <- sapply(with(xx, strsplit(as.character(Sample), "_")), "[", 1)
> xx
> 
> HTH,
> Jorge
> 
> 
> On Aug 18, 2011, at 5:43 PM, 1Rnwb wrote:
> 
>> I have a data frame like this
>> xx<-data.frame(cbind(Sample=c('Ctrl_6h','1+0_6h','1+200_6h','1+5k_6h','Ctrl_5K_6h','ConA_6h'),
>>                IFIT1=c(24,25,24.7,24.5,24.2,24.8)))
>> 
>> grep('[[:digit:]]h',xx$Sample)
>> 
>> yy<-xx$Sample
>> 
>> strsplit(yy,"_")
>> 
>> I have to extract the time information separated by '_' in the sample names,
>> i tried grep and strsplit, it looks that i am not providing some information
>> correctly. I would appreciate if someone can point me to the correct way.
>> Thanks
>> Sharad
>> 
>> --
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>> 
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>