[R] define variables from a matrix
David Winsemius
dwinsemius at comcast.net
Sat Aug 13 18:34:34 CEST 2011
On Aug 12, 2011, at 7:18 PM, gallon li wrote:
> I have a following matrix and wish to define a variable based the
> variable
>
> A=matrix(0,5,5)
> A[1,]=c(30,20,100,120,90)
> A[2,]=c(40,30,20,50,100)
> A[3,]=c(50,50,40,30,30)
> A[4,]=c(30,20,40,50,50)
> A[5,]=c(30,50,NA,NA,100)
>> A
> [,1] [,2] [,3] [,4] [,5]
> [1,] 30 20 100 120 90
> [2,] 40 30 20 50 100
> [3,] 50 50 40 30 30
> [4,] 30 20 40 50 50
> [5,] 30 50 NA NA 100
>
> I want to define two variables:
>
> X is the first column in each row that is equal to 20, for example,
> for the
> first row, I need X=2; 2nd row, X=3; 3rd row, X=NA; 4th row, X=2,
> 5th row,
> X=NA;
X <- apply(A, 1, function(x) which(x==20) )
is.na(X) <- !unlist(lapply(X, length))
X
The first command seems obvious, but the second might be a bit
obscure. It says assign NA to any X whose length is non-zero (i.e.
positive in the case of length).
>
> Y is then the first column in each row that is equal to 100 if
> before this a
> 20 has been reached, for example, for the first row, Y=3; 2nd row,
> Y=5; 3rd
> row, Y=NA, 4th row, Y=NA; 5th row, Y=NA.
Y <- apply(A, 1, function(x) which(x==20)*(which(x==20) <
which(x==100) ) )
is.na(Y) <- !unlist(lapply(Y, length))
Y
--
David.
>
> the matrix may involve NA as well.
>
> How can I define these two variables quickly?
>
> [[alternative HTML version deleted]]
>
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> and provide commented, minimal, self-contained, reproducible code.
David Winsemius, MD
Heritage Laboratories
West Hartford, CT
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