[R] generate two sets of random numbers that are correlated
Duncan Murdoch
murdoch.duncan at gmail.com
Thu Aug 11 19:40:36 CEST 2011
On 11/08/2011 1:33 PM, Duncan Murdoch wrote:
> On 11/08/2011 12:01 PM, Kathie wrote:
> > almost forgot. In fact, I want to generate correlated Poisson random vectors.
>
> Saying you want two random variables to be correlated doesn't specify
> the joint distribution, so there will be a lot of solutions. Here's
> one, for the case where both variables have the same mean mu, and you
> want a positive correlation.
>
> We know that the sum of independent Poissons is Poisson, so we'll
> generate 3 variables: X with mean nu, and Y& Z with mean mu-nu, and return
> A = X+Y and B = X+Z. If nu=0 then A and B are independent, and if
> nu=mu, they have correlation 1, so you must be able to solve for a value
> where they have any desired correlation in between.
>
> If the means aren't the same, this method will still work up to a point,
> but you won't be able to get really high correlations.
>
> If you want negative correlations it's harder, but you could use the
> following trick: Generate U ~ Unif(0, 1). Calculate A by the inverse
> CDF method from U. Compute V to be equal to U if U< a or U> 1-a, and
> equal to 1-U otherwise. Calculate B by the inverse CDF method on V.
>
> Then both U and V will have Poisson distributions (and you can choose
I meant A and B in the line above...
> the means as you like), and there will be some range of achievable
> correlations which will be quite close to [-1, 1]. The joint
> distribution will be very weird, but you didn't say that was a problem...
>
> Some R code:
>
> U<- runif(10000)
> A<- qpois(U, 5)
> a<- 0.115
> V<- ifelse(U< a | U> 1-a, U, 1-U)
> B<- qpois(V, 5)
> cor(A, B)
>
> This gives a correlation around 0.4.
>
>
> Duncan Murdoch
More information about the R-help
mailing list