[R] average among one factor in a nested dataframe
Kenneth Roy Cabrera Torres
krcabrer at une.net.co
Mon Apr 25 13:14:19 CEST 2011
Hi Junquian:
I try your code (there is a typo, I believe)
a<-rnorm(6)
b<-rnorm(9)
f1<-c("x1","x2","x3")
f2<-c("y1","y2")
id<-c(1:6)
a_df<-data.frame(cbind(id,f1,"y1",a))
id<-c(1:9)
b_df<-data.frame(cbind(id,f1,"y2",b))
But I don't understand the "nested" databases.
I see that both have f1 variable but I do not see f2 variable in any of
them. So, what do you mean with "collapse f2"?
Maybe you need to first "merge()" de databases and then "aggregate()"
them.
Have a nice day!
El dom, 24-04-2011 a las 23:42 -0500, Junqian Gordon Xu escribió:
> I have two nested data frames:
>
> a<-rnorm(6)
> b<-rnorm(9)
> f1<-c("x1","x2","x3"))
> f2<-c("y1","y2")
> id<-c(1:6)
> a_df<-data.frame(cbind(id,f1,"y1",a))
> id<-c(1:9)
> b_df<-data.frame(cbind(id,f1,"y2",b))
>
> I want to preserve id and f1, but want to collapse f2 and take the
> corresponding mean values of a and b. Missing value in either dataframe
> should be handled properly (i.e., just take the non-missing number
> without dividing by 2).
>
> I had a look at rowSum/Means and s/l/tapply, but couldn't figure out how
> to handle this case cleanly. Any suggestions?
>
> Thanks
> Gordon
>
> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
More information about the R-help
mailing list