[R] replace last 3 characters of string

jim holtman jholtman at gmail.com
Mon Apr 4 06:46:36 CEST 2011


Will this do it for you:

> x <- c('asdfasdf', 'sadfasdf/:/', 'sadf', 'asdf/:/')
> sub("/:/$", '', x)
[1] "asdfasdf" "sadfasdf" "sadf"     "asdf"

On Sun, Apr 3, 2011 at 7:39 PM, Bert Jacobs
<bert.jacobs at figurestofacts.be> wrote:
> Hi,
>
>
>
> I would like to replace the last tree characters of the values of a certain
> column in a dataframe.
>
> This replacement should only take place if the last three characters
> correspond to the value "/:/" and they should be replaced with ""(blank)
>
> I cannot perform a simple gsub because the characters /:/ might also be
> present somewhere else in the string values and then they should not be
> replaced.
>
>
>
> Could someone help me out on this one?
>
> Thx
>
> Bert
>
>
>
>
>
>
>        [[alternative HTML version deleted]]
>
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>



-- 
Jim Holtman
Data Munger Guru

What is the problem that you are trying to solve?



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