[R] the function doesn´t work

[Bill.Venables at csiro.au]

This is worse than before and getting pretty silly.  Now you are calling outer with a function that only takes one argument.  

R might be hard for you, but mind reading is even harder for most of us.  To get help you need to explain clearly and sensibly what it is you want to do.

Look at your code.  You generate (the same) random numbers every time and do not use them.  diag(cor(x,y)) is always a vector of ones.  So p is the same at every stage of the loop as well.  You put q_1 and q_2 inside the loop, but only use the outside.  This is not R, this is just a failure to think clearly about what you are doing.

-----Original Message-----
From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org] On Behalf Of jethi
Sent: Sunday, 26 September 2010 5:29 PM
To: r-help at r-project.org
Subject: Re: [R] the function doesn´t work


hi, sorry but i can´t remove the problem.but i change the programm a little
bit. i didn´t work with r programm before, so its really hard for me to find
my problems. :) 


N=5
n=100


p_0=c(1/5,1-1/5)

power = function(k1) {
set.seed(1000)
H=matrix(0,nrow=N,ncol=1)

for(i in 1:N) {

 x <- matrix(rnorm(n, 0, 0.5), ncol =m1)
 y <- matrix(rnorm(n, 0, 0.8), ncol = m1)
 l <- diag(cor(x, y))



q_1 = qnorm(0.05, 0, 0.05)
   q_2 = qnorm(1 - 0.05, 0, 0.05)
p <- (l^2)/sum(l^2)

H[i] <- sum(p_0*log(p_0))  - sum(p * log(p))

}
1- mean(q_1 <= H & H <= q_2)

}
m1=seq(0,n/2,len=10)
k1=1/m1
output <- power(k1)
f=outer(k1,Vectorize(power))
-- 
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