[R] For loop with ifelse help
Pele
drdionc at yahoo.com
Wed Sep 22 17:42:50 CEST 2010
Hello R users,
I have 2 files (file1 and f2) and I am trying to sum columns 6:10 of a
specific row in f2 and append it in
file 1 if the "state" variable in file 1 equals the rowname in f2. Below is
an example of the code I wrote
using a for loop, but it not working (i.e it only works for the last number
(10) in the loop). Can someone tell me how to fix?
Many thanks !
file1 <- data.frame(ID=seq(1:30), state=sample(1:10, 30, replace=TRUE));
file1
ID state
1 1 7
2 2 7
3 3 6
4 4 4
5 5 5
6 6 7
7 7 10
8 8 1
9 9 1
10 10 5
............
.........
file2 <- matrix(seq(1:100),nrow=10)
f2 <- as.data.frame(file2); f2
V1 V2 V3 V4 V5 V6 V7 V8 V9 V10
1 1 11 21 31 41 51 61 71 81 91
2 2 12 22 32 42 52 62 72 82 92
3 3 13 23 33 43 53 63 73 83 93
4 4 14 24 34 44 54 64 74 84 94
5 5 15 25 35 45 55 65 75 85 95
6 6 16 26 36 46 56 66 76 86 96
7 7 17 27 37 47 57 67 77 87 97
8 8 18 28 38 48 58 68 78 88 98
9 9 19 29 39 49 59 69 79 89 99
10 10 20 30 40 50 60 70 80 90 100
for (i in length(f2)) {
file1$chksum <- ifelse ((file1$state==rownames(f2)[i]),
rowSums(f2[rownames(f2)[i], 6:10]), 0)
}
print(file1)
ID state chksum
1 1 7 0
2 2 7 0
3 3 6 0
4 4 4 0
5 5 5 0
6 6 7 0
7 7 10 400
8 8 1 0
9 9 1 0
10 10 5 0
11 11 10 400
12 12 9 0
13 13 10 400
14 14 9 0
15 15 5 0
16 16 3 0
17 17 1 0
18 18 7 0
19 19 7 0
20 20 2 0
21 21 3 0
22 22 8 0
23 23 8 0
24 24 4 0
25 25 6 0
26 26 6 0
27 27 3 0
28 28 3 0
29 29 5 0
30 30 5 0
--
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