[R] Weibull simulation- number of items to replace is not a multiple of replacement length
Phil Spector
spector at stat.berkeley.edu
Thu Sep 16 23:03:43 CEST 2010
Perhaps the following will be instructive:
> mymat = matrix(1:6,3,2)
> p = 1
> mymat[p]
[1] 1
> mymat[p,]
[1] 1 4
When you index a matrix by a single subscript, it returns a
single element, corresponding to the columnwise vector representation
of the matrix. I'm guessing you want to put the estimates into
the pth row (mymat[p,]) or pth column (mypat[,p]) of the matrix.
- Phil Spector
Statistical Computing Facility
Department of Statistics
UC Berkeley
spector at stat.berkeley.edu
On Thu, 16 Sep 2010, Halabi, Anan wrote:
> Hi,
> I write below code for simulation for weibull- estimating parameters by weibullMLE function,
> Although I define metrix for the variables still I got this message: number of items to replace is not a multiple of replacement length
> Any suggestion
>
>> est=matrix (NA, 2,2)
>> se=matrix (NA, 2,2)
>> for ( p in 1:2) {
> + sampleSize <- 20
> + shape.true <- 1.82
> + scale.true <- 987
> + sampWB <- urweibull(sampleSize, shape=shape.true, scale=scale.true, lb=0, ub=Inf)
> + sampWBmleWB <- weibullMLE(sampWB)
> + est[p]= sampWBmleWB$estimate
> + se [p]= sampWBmleWB$s
> + }
> Warning messages:
> 1: In est[p] = sampWBmleWB$estimate :
> number of items to replace is not a multiple of replacement length
> 2: In se[p] = sampWBmleWB$s :
> number of items to replace is not a multiple of replacement length
> 3: In est[p] = sampWBmleWB$estimate :
> number of items to replace is not a multiple of replacement length
> 4: In se[p] = sampWBmleWB$s :
> number of items to replace is not a multiple of replacement length
>> est
> [,1] [,2]
> [1,] 1.507558 NA
> [2,] 1.525856 NA
>> se
> [,1] [,2]
> [1,] 0.2513083 NA
> [2,] 0.2709073 NA
>
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