[R] Number of occurences of a character in a string

(Ted Harding) ted.harding at wlandres.net
Mon Oct 11 10:20:41 CEST 2010


How about:

  sum(unlist(strsplit(b,NULL))==";")
  # [1] 5

(More transparent, at least to me ... ). See '?strsplit',
and note what is said under "Value".

Ted.

On 11-Oct-10 04:35:43, Michael Sumner wrote:
> Literally:
> 
> length( gregexpr(";", b)[[1]])
> 
> But more generally, in case b has more than one element:
> 
> sapply(gregexpr(";", b), length)
> 
> ?gregexpr
> 
> 
> 
> On Mon, Oct 11, 2010 at 3:18 PM, Santosh Srinivas <
> santosh.srinivas at gmail.com> wrote:
> 
>> New to R ... which is a function to most effectively search the number
>> of
>> occurrences of a character in a string?
>>
>> b <-
>> c("jkhrikujhj345hi5hiklfjsdkljfksdio324j';;'lfd;g'lkfit34'5;435l;43'5k"
>> )
>>
>> I want the number of semi-colons ";" in b?
>> Thanks.

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Date: 11-Oct-10                                       Time: 09:20:36
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