[R] Error when using anova(lm())
Alison Callahan
alison.callahan at gmail.com
Fri Oct 8 19:09:29 CEST 2010
See below.
On Fri, Oct 8, 2010 at 1:01 PM, David Winsemius <dwinsemius at comcast.net> wrote:
>
> On Oct 8, 2010, at 12:46 PM, Alison Callahan wrote:
>
>> Hello all,
>>
>> I am trying to perform an ANOVA on some data in a data frame, but when
>> I try to use lm(), I get the following error:
>>
>> Error in storage.mode(y) <- "double" :
>> invalid to change the storage mode of a factor
>> In addition: Warning message:
>> In model.response(mf, "numeric") :
>> using type="numeric" with a factor response will be ignored
>>
>> Here is a subset of my data:
>>
>> island_id refseq_better total refseq_proportion
>> fiveprime threeprime island_size
>> 1a 29 57 0.508771929824561
>> 11127 201378 190251
>> 1c 27 90 0.3
>> 6303879 6600994 297115
>> 1d 33 115 0.28695652173913
>> 7001283 7421591 420308
>> 2b 11 42 0.261904761904762
>> 4381375 4520137 138762
>> 2d 27 81 0.333333333333333
>> 5203929 5497271 293342
>> 3a 44 141 0.312056737588652
>> 28792 552044 523252
>>
>> When I use sapply(dataframe,mode) to check the modes of the columns,
>> this is my output:
>>
>> island_id refseq_better total
>> refseq_proportion
>> "numeric" "numeric" "numeric" "numeric"
>> fiveprime threeprime island_size
>> "numeric" "numeric" "numeric"
>
> So?
>
>> mode(factor(1:10))
> [1] "numeric"
>
> Storage mode is not the right question. "class" is the correct question.
> Best would be to try is.factor()
Looking at the error message, the problem does appear to be with
storage mode ... is this affected by whether the variables are
factors? Note this part of the error:
Error in storage.mode(y) <- "double" :
invalid to change the storage mode of a factor
>
>
>> How do I need to change the format of my data frame so that I do not
>> get the above error?
>
> Figure out which of your columns are factors and apply the FAQ 7.12
>
> --
> David.
>>
>> Thanks!
>>
>> Alison Callahan
>> PhD candidate
>
>
> David Winsemius, MD
> West Hartford, CT
>
>
Thanks,
Alison
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